Example 26.3. A shunt generator delivers 450 A at 230 V and the resistance of the shunt field and armature are 50 Q and 0.03 Qrespectively. Calculate the generated e.m.f. Solution. Generator circuit is shown in Fig. 26.46. Ish I = 450 A Current through shunt field winding is 230/50 = 4.6 A la Load current I= 450 A :. Armature current I,= I+Ih 230 V = 450 + 4.6 = 454.6 A Armature voltage drop IR. 454.6 x 0.03 = 13.6 V Fig. 26.46 coad ell U OS

Example 26.3. A shunt generator delivers 450 A at 230 V and the resistance of the shunt field and armature are 50 Q and 0.03 Qrespectively. Calculate the generated e.m.f. Solution. Generator circuit is shown in Fig. 26.46. Ish I = 450 A Current through shunt field winding is 230/50 = 4.6 A la Load current I= 450 A :. Armature current I,= I+Ih 230 V = 450 + 4.6 = 454.6 A Armature voltage drop IR. 454.6 x 0.03 = 13.6 V Fig. 26.46 coad ell U OS

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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