EXAMPLE 2: A compound channel is shown in Fig 2.7b. It has the following dimensions: m, = 1, n, = 0.03, b, = 10m, d, = 2m. The upper part of the channel has the following dimensions m2 = 1.5, n2 = 0.0225, b2 = 5m, d2 = 1.5m. The channel bottom slope is So = 0.0003. Determine the (i) channel discharge (ii) Average velocity at the cross section. %3D

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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EXAMPLE 2: A compound channel is shown in Fig 2.7b. It has the following dimensions: m, =
1, n, = 0.03, b, = 10m, d, = 2m. The upper part of the channel has the following dimensions m,
= 1.5, n2 = 0.0225, b2 = 5m, d2 = 1.5m. The channel bottom slope is S, = 0.0003. Determine the
(i) channel discharge (ii) Average velocity at the cross section.
Solution:
nj=0.03
n2=0.0225
n3=0.03
d;=2m
1
1
di=2m
1
bi=10m
d2=1.5m
b3=10m
b2=5m
Fig 2.7 b
Transcribed Image Text:EXAMPLE 2: A compound channel is shown in Fig 2.7b. It has the following dimensions: m, = 1, n, = 0.03, b, = 10m, d, = 2m. The upper part of the channel has the following dimensions m, = 1.5, n2 = 0.0225, b2 = 5m, d2 = 1.5m. The channel bottom slope is S, = 0.0003. Determine the (i) channel discharge (ii) Average velocity at the cross section. Solution: nj=0.03 n2=0.0225 n3=0.03 d;=2m 1 1 di=2m 1 bi=10m d2=1.5m b3=10m b2=5m Fig 2.7 b
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