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Example 10.6 Examine the stability of s³ + 25 +45³ +85² + 3s + 1 = 0 using Routh's criteria. Solution || در 4 3 S28 1 S³0 2.5 0 5² 8 -Routh's array failed. To remove the above difficulty, the following two methods can be used. Method 1: (i) Replace 0 by E (a small number) and complete the array with E. (ii) Examine the sign change by taking & → 0. The above example is solved below. 4 3 81 2.5 0 کی S2 SE 2 $² 8E-5 3 2.5 8E-5 E 8E-5 E 10 0

Example 10.6 Examine the stability of s³ + 25 +45³ +85² + 3s + 1 = 0 using Routh's criteria. Solution || در 4 3 S28 1 S³0 2.5 0 5² 8 -Routh's array failed. To remove the above difficulty, the following two methods can be used. Method 1: (i) Replace 0 by E (a small number) and complete the array with E. (ii) Examine the sign change by taking & → 0. The above example is solved below. 4 3 81 2.5 0 کی S2 SE 2 $² 8E-5 3 2.5 8E-5 E 8E-5 E 10 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Example 10.6 Examine the stability of s³ +254 + 45³ +85² + 3s +1=0 using Routh's criteria. Solution s³|1 4 3 S28 1 $³0 2.5 0 5² 8 ←Routh's array failed. To remove the above difficulty, the following two methods can be used. Method 1: 3 (i) Replace 0 by E (a small number) and complete the array with E. (ii) Examine the sign change by taking & → 0. The above example is solved below. $$ 4 3 S2 $³ 8E-5 33 *** E 2.5 *** 8ɛ E 8E-5 E I B 81 2.5 0 10 How did he get the final output? It is possible to explain step by step and with a clear line
Transcribed Image Text:Example 10.6 Examine the stability of s³ +254 + 45³ +85² + 3s +1=0 using Routh's criteria. Solution s³|1 4 3 S28 1 $³0 2.5 0 5² 8 ←Routh's array failed. To remove the above difficulty, the following two methods can be used. Method 1: 3 (i) Replace 0 by E (a small number) and complete the array with E. (ii) Examine the sign change by taking & → 0. The above example is solved below. $$ 4 3 S2 $³ 8E-5 33 *** E 2.5 *** 8ɛ E 8E-5 E I B 81 2.5 0 10 How did he get the final output? It is possible to explain step by step and with a clear line
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