Example 1.1. The point P(-2,2) lies on the curve y = √2-x. (1) Sketch the curve and the tangent line at P.

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Chapter1: Functions And Models
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Example 1.1. The point P(-2,2) lies on the curve y = √2-x.
(1) Sketch the curve and the tangent line at P.
(2) If Q is the point (x, √2-x), find the slope of the secant line PQ (correct to
six decimal places) for the following values of x:
(i) -2.5 (ii) -2.1 (iii) -2.01 (iv) -2.001
(v) -1.5 (vi) -1.9 (vii) -1.99 (viii) -1.999
Solution
x
√2-x
m sec
-2.5
2.121320344
-0.242641
(ii)
-2.1 2.024845673
-0.248457
-0.249844
(iii) -2.01 2.002498439
(iv) -2.001 2.000249984 -0.249984
(v) -1.5 1.870828693 -0.251582
(vi) -1.9 1.974841766 -0.258343
(vii) -1.99 1.997498436 -0.250156
(viii) -1.999 1.999749984 -0.250016
1
Transcribed Image Text:Example 1.1. The point P(-2,2) lies on the curve y = √2-x. (1) Sketch the curve and the tangent line at P. (2) If Q is the point (x, √2-x), find the slope of the secant line PQ (correct to six decimal places) for the following values of x: (i) -2.5 (ii) -2.1 (iii) -2.01 (iv) -2.001 (v) -1.5 (vi) -1.9 (vii) -1.99 (viii) -1.999 Solution x √2-x m sec -2.5 2.121320344 -0.242641 (ii) -2.1 2.024845673 -0.248457 -0.249844 (iii) -2.01 2.002498439 (iv) -2.001 2.000249984 -0.249984 (v) -1.5 1.870828693 -0.251582 (vi) -1.9 1.974841766 -0.258343 (vii) -1.99 1.997498436 -0.250156 (viii) -1.999 1.999749984 -0.250016 1
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