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Example 1: In the figure, assuming clockwise moments as positive, compute the moment of force F = 450lbs and force P = 361|bs about points A, B, C and D

Example 1: In the figure, assuming clockwise moments as positive, compute the moment of force F = 450lbs and force P = 361|bs about points A, B, C and D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Example 1: In the figure, assuming clockwise moments as positive, compute the moment of force F = 450lbs and force P = 361lbs about points A, B, C and D Given: F = 450 Ibs P = 361 Ibs Required: ME, ME, ME, M5 MÅ. M. M², M, Solution: MA = -F(d,) = -450(3) = -1350ft lb 3 Fy = - (F) = =(450) = 270 F =3 (F) Mỹ = Ma + MA = -F,(3) – F,(1) = -360(3) – 270(1) = -1350ft lbs ==(450) = 360 MẸ = M3 + 1 = +F,(3) + F,(4) = 360(3) + 270(4) = 2160ft Ibs ME = > Mc + -Σ. Mỹ = +F,(0) + F,(5) = 0 + 270(5) = 1350ft lbs %3D M5 Mp +a M5 = F,(3) – F,(1) = 360(3) – 270(1) = 810ft lbs Assignment: Solve for P
Transcribed Image Text:Example 1: In the figure, assuming clockwise moments as positive, compute the moment of force F = 450lbs and force P = 361lbs about points A, B, C and D Given: F = 450 Ibs P = 361 Ibs Required: ME, ME, ME, M5 MÅ. M. M², M, Solution: MA = -F(d,) = -450(3) = -1350ft lb 3 Fy = - (F) = =(450) = 270 F =3 (F) Mỹ = Ma + MA = -F,(3) – F,(1) = -360(3) – 270(1) = -1350ft lbs ==(450) = 360 MẸ = M3 + 1 = +F,(3) + F,(4) = 360(3) + 270(4) = 2160ft Ibs ME = > Mc + -Σ. Mỹ = +F,(0) + F,(5) = 0 + 270(5) = 1350ft lbs %3D M5 Mp +a M5 = F,(3) – F,(1) = 360(3) – 270(1) = 810ft lbs Assignment: Solve for P
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