Ex.1. Consider a fiber in air with no=1, n¡=1.53, and n2=1.5. Calculate and draw a ray diagram for the following: a) The smallest value of the internal angle (i.e. O.), b) The maximum angle the ray in air makes with the fiber axis, c) A and NA. (ans.:78.6°, 17.6°, 0.019, 0.30).
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- An incident ray striko a glaus (n=152) w gle qf 38% to the surface Of with an angle of 牛3p0 the glass. UF with abel angie Of ncidence, angle f peplected 代とractoo no a. illustrate ray and angle e Pe ¢rachion. re. b. what is the argle of the teglec tetd ray? JusrThe figure shows a refracted light beam in linseed oil making an angle of p = 16.0° with the normal line NN'. The index of refraction of linseed oil is 1.48. Air N Linseed oil $1 (a) Determine the angle 8. (b) Determine the angle 0¹. Water9. A beam of light initially passing through oil (noil = 1.45) is incident on water (nwater = 1.3) at an angle of 0; = 60°. The critical angle for these two substances is 63.7°. Which of the following statements is true? a) 100% of the incident beam is transmitted into water. b) 100% of the incident beam is reflected back into oil. c) Some portion of the incident beam is transmitted and the remainder is reflected. d) More information is needed to choose the best answer.
- Building contractors often install double-glazed windows to prevent thermal energy (heat) from entering or exiting a building. In addition to being effective insulators, such windows present interesting optical effects. glass In the figure, a double-glazed window consists of two identical panes of glass (ng = 1.46), each yg = 12.0 mm air thick, separated by an air gap of y, = 9.60 mm. If light incident on the glass makes an angle of o = 40.00° with respect to the glass, find the shift in path Ax as the light glass enters the room. Use na = 1.00 for the index of refraction of air. Ax = mmNeeds Complete typed solution with 100 % accuracy.We know that the index of refraction of materials can help identify those materials. A light beam is shined onto a surface a reflected ray and is found to be completely polarized when the angle of incidence is 53.5°.(a) What is the index of refraction of the reflecting material? (b) What is the angle of refraction if some light passes through the surface of the material?°
- Ex.2. Consider a fiber is immersed in water with n,=1.33, n¡=1.53, and n2=1.5. Calculate and draw a ray diagram for the following: d) The smallest value of the internal angle (i.e. O.), e) The maximum angle the ray in air makes with the fiber axis, ) Δ and ΝΑ.Optical fibers are a central part of technology for rapid information transmission with a high level of efficiency. A new type of optical fiber is crafted with an index of refraction n = less than that of water in the vicinity of room temperature, where NH2O fact that n < nH20 potentially problematic if the fiber should be submerged? 1.25 = 1.33. Why is the O A. Total internal reflection would be frustrated, allowing loss of signal. O B. Internal reflection would actually be enhanced, so there is no problem. C. Electric eels might have free internet access.A small lamp at the bottom of a pool of 2 m deep in water (n = 4/3), emits light upwards in all directions (isotropic source). On the surface of the water, a circular illuminated area appears due to the refraction of the light rays. Determine the radius R of this illuminated area.
- In the above figure, theta (the angle the incident ray makes with respect to the vertical) is 26.0 degrees. What is d (the distance between the ray emerging from the bottom of the glass and where the ray would have been if it had continued straight on with no glass to refract it)?The figure shows a refracted light beam in linseed oil making an angle of ? = 15.8° with the normal line NN'. The index of refraction of linseed oil is 1.48. a) Determine the angle ?. b) Determine the angle ?'.2. A small light source (point source) is located in water (nr 1.33) at a depth d below the surface. Determine (a.) the critical angle for total reflection of light at the water-air interface (b.) the depth of the light source if an observer above the water sees an illuminated circle of 3m radius.