Ex. 30 : A particle of mass 5 gm performs S.H.M. along a straight line 20 cm long with frequency 120 r.p.m. If it starts its motion from the mean position, find its (1) displacement (2) velocity (3) acceleration (4) P.E. at the end of th second. 12

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A: Given:-              Position                              s t = -t3 +18 t2 - 81 t

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Q: image489

A: The detailed explanation of Q9 is given below. Please repost the question for further assistance.

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A: The position the particle is given by X(t) = 5t^2  - 8t + 3

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A: Have a look

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Q: 1. The position of the particle is given by s = (9t^3 – 6t^2 – 32t + 16) meters, where t is in…

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A: As per guidelines, first three questions has been answered. The plot is given below.

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A: Velocity Vx=dx/dt  =-5wcoswt  Vy=dy/dt  =5wsinwt

Q: v (m/s) [N] vs t (s) 15 10 -5 -10 10 15 20 25 30 t (s) INI (s/u) A

A: The solution can be given as follows :-

Q: please explain the given plot

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