Ex: For the system methanol (1) /methyl acetate (2), the following equation provide a reasonable correlation for the activity coefficients: In Y₁ = AX2, In Y2 = AX² Where A = 2.771 -0.00523T 21.1071 In addition, the following Antoine equations provide vapor pressures: In P₁ = 16.59158- In P₂ = 14.25326- - 3643.31 T-33.424 - (a) P and (y) for T=318.15 K and x₁ = 0.25. (b) P and (x) for T=318.15 K and y₁ = 0.60. (c) T and (y) for P= 101.33 kPa and x₁ = 0.85. (d) T and (x) for P = 101.33 kPa and y₁ = 0.40. 2665.54 T-53.424 Where T is in kelvins and the vapor pressures are in kPa. Assuming the val of Eq. (13.19), calculate:
Ex: For the system methanol (1) /methyl acetate (2), the following equation provide a reasonable correlation for the activity coefficients: In Y₁ = AX2, In Y2 = AX² Where A = 2.771 -0.00523T 21.1071 In addition, the following Antoine equations provide vapor pressures: In P₁ = 16.59158- In P₂ = 14.25326- - 3643.31 T-33.424 - (a) P and (y) for T=318.15 K and x₁ = 0.25. (b) P and (x) for T=318.15 K and y₁ = 0.60. (c) T and (y) for P= 101.33 kPa and x₁ = 0.85. (d) T and (x) for P = 101.33 kPa and y₁ = 0.40. 2665.54 T-53.424 Where T is in kelvins and the vapor pressures are in kPa. Assuming the val of Eq. (13.19), calculate:
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Ex: For the system methanol (1) /methyl acetate (2), the following equations
provide a reasonable correlation for the activity coefficients:
In Y₁ = AX2, In Y2 = AX²
Where A = 2.771 -0.00523T
211071
In addition, the following Antoine equations provide vapor pressures:
In P₁ = 16.59158.
In P₂ = 14.25326 -
3643.31
T-33.424
Where T is in kelvins and the vapor pressures are in kPa. Assuming the validity
of Eq. (13.19), calculate:
(a) P and (y) for T=318.15 K and x₁ = 0.25.
P and (x) for T=318.15 K and y₁ = 0.60.
(c) T and (y) for P= 101.33 kPa and x₁ = 0.85.
(d) T and (x) for P= 101.33 kPa and y₁ = 0.40.
дзна
2665.54
T-53.424
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