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Ex: Estimate the value of №.1.5 by..binamia.. sevies. Sol 4.5 = (1+015.) ². X=0.³.5 m = 0.15... 3 •: √1.25= +01.5 (015.) +015 (015-1) (01.5.) ² + 015 (015-1) (015-2) (015) 21 31 1375 =1+0.25 +0.25. (0.2.5.).. + ..(.0...12.5.)....... 8 1+0.25 -0.0.3125 +0.00.7.8 = 1.226.5.5... ८ *******

Ex: Estimate the value of №.1.5 by..binamia.. sevies. Sol 4.5 = (1+015.) ². X=0.³.5 m = 0.15... 3 •: √1.25= +01.5 (015.) +015 (015-1) (01.5.) ² + 015 (015-1) (015-2) (015) 21 31 1375 =1+0.25 +0.25. (0.2.5.).. + ..(.0...12.5.)....... 8 1+0.25 -0.0.3125 +0.00.7.8 = 1.226.5.5... ८ *******

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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***** EX Estimate the value of 1.1.5 by binamial series. Sol: √1.5 = (1+0.5.)?² X=0.³.5 m = 0.15... √√1.251+0+5 (0×5) + 015 (015-1) (01.5.)² +015 (015-1) (015-2) (0.5) 21 31 01375 =1+0+25 +0.25 (0.2.5.)... + ..(.0...12.5.).. 8 1+01·25 0.0.3125 + 0.00.7.8 = 1.226.5.5... Clarify the solution to the question step by step and in a clear line
Transcribed Image Text:***** EX Estimate the value of 1.1.5 by binamial series. Sol: √1.5 = (1+0.5.)?² X=0.³.5 m = 0.15... √√1.251+0+5 (0×5) + 015 (015-1) (01.5.)² +015 (015-1) (015-2) (0.5) 21 31 01375 =1+0+25 +0.25 (0.2.5.)... + ..(.0...12.5.).. 8 1+01·25 0.0.3125 + 0.00.7.8 = 1.226.5.5... Clarify the solution to the question step by step and in a clear line
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