Ex:Design a digestion tank for the primary sludge with the help offollowing data :(i) Average flow = 20 Mld ;(ii) Total suspended solids in raw sewage(iii) Moisture content of digested sludge = 85%.Assume any other suitable data you require.%3D300 mgll ;%3D

Answered: Image /qna-images/answer/94500bfb-7856-4b01-8856-0031ec40837e.jpg

Ex: Design a digestion tank for the primary sludge with the help of following data : (i) Average flow (ii) Total suspended solids in raw sewage (iii) Moisture content of digested sludge = 85%. 20 Mld; %3D 300 mgll ; Assume other suitable data you require. any

Ex: Design a digestion tank for the primary sludge with the help of following data : (i) Average flow (ii) Total suspended solids in raw sewage (iii) Moisture content of digested sludge = 85%. 20 Mld; %3D 300 mgll ; Assume other suitable data you require. any

Solid Waste Engineering

3rd Edition

ISBN:9781305635203

Author:Worrell, William A.

Publisher:Worrell, William A.

Chapter6: Biological Processes

Section: Chapter Questions

Problem 6.1P

See similar textbooks

Related questions

Q: A mixed liquor sample form an activated sludge plant was settled in a one-litre measuring cylinder…

Q: (b) Consider the following data for a completely mixed activated sludge system to treat wastewater…

Q: Digester volume = 40,000 ft, Raw sludge volume 5,000 gpd, Sludge concentration %3D = 5% Volatile…

Q: Problem 1. A wastewater sample is examined for its solid contents. The ionic strength (μ) of…

A: (a). The concentration of organic solids in the wastewater sample. Since 30% of TDS is organic, the…

Q: SS=4,000 mg/L raw wastewater has the following characteristics: w=12 MGD Os=220 mg/L pended solids…

Q: A untreated waste water enters a stream as shown in figure. The concentration of sodium in the…

A: Given data, The concentration of sodium =15 mg/l flow rate=20 m3 /sec The concentration of sodium in…

Q: •Given the following information for wastewater plant, the plant is an activated sludge system with…

A: Answer Flow rate Q = 60000 m3/d Volume of Aeration tank = 7500 m3 Efficiency of aeration tank = 85%…

Q: How to determine the needed surface area of the secondary clarifier tank given that the flow is…

A: The following is the given information. The flow is 40000 m3/day. The recycling ratio is 0.5. The…

Q: Solids analysis is one of the most widely used parameters for assessing water quality. Use the…

A: Given, Tare mass of evaporating dish=4.3520 g Mass of evaporating dish plus residue after…

Q: Q-3: A river before its entry into a town had a discharge of 100 1/sec and 20 mg/L as the…

Q: C- During preliminary treatment of a sewage, the following poll removed: 1. Oil and grease are…

A: During preliminary treatment of a sewage, the following pollutions are removed: 4.All the above.

Q: sing alum at 23 mg/litre. No o ncentration is 37 mg/l. The efm and specific gravity of sludge is =

Q: A wastewater stream A with 200 m3 /h of flow rate an mixes with stream B having flow rate of 400m3/h…

Q: • An average operating data for conventional activated sludge treatment plant is as follow:-…

Q: Using the data presented below, compute the total amount of sludge produced daily in the primary…

A: please find attached solution below.

Q: The PEF, Inc. firm desires to utilize a complete-mix activated-sludge system with recycle to treat…

A: Given, MLVSS (X) = 2500 mg/L Influent soluble BOD5 (So) = 292 mg/L θc = 7.24 days Effluent BOD5…

Q: Based on the Sieve Analysis results for filter media given below: Size of Opening (mm) Cumulative…

A: Given the results of Sieve analysis test results for filter media. The effective size = d10 : It is…

Q: Q2: A coagulation treatment plant with a flow of 0.5 m/sec is dosing alum at 23 mg/l. No other…

Q: A coagulation treatment plant with a flow of 0.5 m3/s is dosing alum at 20 mg/l. Concentration of…

A: According to given data A coagulation treatment plant with a flow of 0.5 m3/s is dosing alum at 20…

Q: A laboratory provides the following solids analysis for a wastewater sample: TS = 290 mg/L; TDS = 37…

A: Total solidsTS=290 mg/lTotal dissolved solidsTDS=37 mg/lFixed suspended solidsFSS=38 mg/la…

Q: The quantity of sludge produced from an aeration tank is 2,453 kg/day. The volume of the aeration…

A: The sludge loading is X=2453 kg/day. The volume of aeration tank is V=8500 m3. The inlet BOD is…

Q: Q.1) a. Calculate volume and weight of sludge generated in thickener by chemical coagulation. Data…

Q: The data of an activated sludge process are B. as follows: MLSS = 5000 mg/lit %3D Flow = 0.15 m3/sec…

Q: T Settled sludge and filter wash water from water treatment are thickened in Problems 703…

A: Daily Quantity of Thickened SludgeWe can calculate the daily quantity of thickened sludge using the…

Q: Direction: An activated sludge system (sketched below) is operating at equilibrium with the…

Q: Design a gravity thickener to concentrate the mixture of sludge obtained from primary and secondary…

A: Given: Sludge waste flow rate in the primary settling unit= 140 m³/d; Sludge waste concentration in…

Q: AA רואד רחר בורו Determine the size (diameter and depth) of the secondary clarifier (s) at a…

A: Step 1

Q: The bioreactor volume (V), F/M ratio, and HRT are respectivel O 250 million gallons, 0.28…

A: A continuous stirred tank reactor (CSTR) Activated Sludge Process is used to treat municipal…

Q: A raw sewage sample was brought in for total suspended solids and volatile solids analysis. A…

Q: Water treatment plant : SOR = 0.35 mm/sec; The analysis of this water found that there are 6…

Q: 6. After your flash mix the water was sent to a clarification basin that was 24 feet in diameter and…

A: To find:-detention tiefiltration ratefiltration rate after breakthrough failure

Q: The following data on the substrate removal rate and the substrate concentration is available for…

A: We are using Michaelis-Menten equation

Q: Q-The MLSS concentration in an aeration tank is 2000 mg/l and the sludge volume after 30 minutes of…

A: Given data- MLSS concentration Xs =2000 mg/L, Sludge volume Vs =175 mL, Time t=30 min, Graduated…

Q: 3. A 100 mL of wastewater sample was drying on a 0.5 g empty dish weight at 104 °C to weight 0.5625…

A: Volume of sample = 100 ml=1001000=0.1 l Initial weight of sample = 0.5 g Final weight of sample =…

Q: Design the following items for an aerated grit chamber for the treatment of municipal wastewater.…

Concept explainers

Integrated Solid Waste Management

Integrated Solid Waste Management (ISWM) is a thorough waste suppression, compost, removal and recycling Program. An effective ISWM system considers how to suppress, manage and recycle solid waste in a manner that is most efficiently to protect human health and the surrounding. ISWM system requires evaluation of public wants and demands and then selecting and merging the most effective waste management activities for the proposed demands. The main ISWM activities for solid waste management are Waste prevention, Recycling and Composting, and Combustion and Removal and waste collection in a properly planned, constructed, managed and mitigated landfill areas. Each of these requires careful designing, financing, accumulation, and delivery of activities.

Question

Ex:
Design a digestion tank for the primary sludge with the help of
following data :
(i) Average flow = 20 Mld ;
(ii) Total suspended solids in raw sewage
(iii) Moisture content of digested sludge = 85%.
Assume any other suitable data you require.
%3D
300 mgll ;
%3D

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Design the following items for an aerated grit chamber for the treatment of municipal wastewater. Using two grit chambers. The required data for design is listed in table below. The average flow rate Peaking factor The average detention time at peak flowrate The width: depth ratio Depth Air supply per unit of length Grit quantity per day at peak flow 0.45 m3/s 3 min 1.25: 1.0 3.0 m 0.5 m³/m. min 0.05 m³/103 m³
Problem 1. A wastewater sample is examined for its solid contents. The ionic strength (μ) of wastewater is 0.01. It is known that 30% of total dissolved solids (TDS) is organic. The volumetric settleable solid concentration is determined as 20 mL/L using Imhoff Cone. It is assumed that 40% of total suspended solids (TSS) is equal to dry-settleable solids. The volumetric settleable solids composes of 2% of dried solids and 98% of water. The density of volumetric settleable solid concentration is given as 1020 g/L. Use information given in problem, calculate: a) Total Dissolved Solids (TDS) concentration as mg/L. b) Total Suspended Solids (TSS) concentration as mg/L. c) Total Solids (TS) concentration as mg/L.
C- During preliminary treatment of a sewage, the following pollu removed: 1. Oil and grease are removed from skimming tanks 2. Floating materials are removed by screening. 3. Grit and sand are removed by grit chambers. 4. All the above. es consists of:
Q2: A coagulation treatment plant with a flow of 0.5 m/sec is dosing alum at 23 mg/l. No other chemical is being added. The raw water suspended solids concentration is 37 mg/l. The effluent suspended solids concentration is measured as 12 mg/l. The sludge content is 1% and the specific gravity of sludge solids is 3.01. What volume of sludge must be disposed of each day? Based on your result, remark with tolerance to water treatment process.
A coagulation treatment plant with a flow of 0.5 m/s is dosing alum at 23 mg/litre. No other chemicals are being added. The raw water suspended solid concentration is 37 mg/l. The effluent suspended solid concentration is 12 mg/l. Sludge content is 1% and specific gravity of sludge is 3.01. What volume of sludge must be disposed of every day.
A wastewater stream A with 200 m3 /h of flow rate and BOD of 300mg/I mixes with stream B having flow rate of 400m3/h and BOD 225mg/l. A completely mixed activated sludge process is used to treat the mixture. BOD of effluent stream is 10 mg/l. Given Y= 0.5, k=5 day", Kd=0.06 day ; Ks=100 mg/l and MLVSS= 2000 mg/l. Assume all other parameters if necessary Find (a) BOD and flow rate of mixture (b) Mean residence time (c) Oxygen requirement (d) F/M ratio (e) Recycle ratio (f) Sizing of the tank
Give me right solution with detailed calculations
An aeration basin for an activated sludge facility has the following characteristics Length = 90 ft Width = 30 ft Liquid depth = 12 ft MLSS=4,000 mg/L The raw wastewater has the following characteristics: Flow = 12 MGD BOD, = 220 mg/L Suspended solids (SS) = 250 mg/L A primary clarifier is ovided that removes 25% of the BOD, an 60% of the suspended solids The return activated-sludge flow rate is 0.8 MGD If the primary sludge solids content is 4% solids and the specific gravity is 1.0, the primary sludge volume (ft³/day) is most nearly OA. 1,500 OB. 60,000 O C.600 O D.4,500
Please no written by hand solutions
A mixed liquor sample form an activated sludge plant was settled in a one-litre measuring cylinder for 30 minutes after which time, a volume of 350 m/ of sludge was recorded. When 50 m/ of the mixed liquor were filtered through a GFC paper for the determination of MLSS the gain in weight of the paper was 0.1375 g. Determine the SVI.
C. What is the concentration UI SUINUS 5. Determine the size (diameter and depth) of the secondary clarifier (s) at a municipal activated sludge treatment facility: The wastewater flow is 25,000 m³/d, the recycle ratio (recycle sludge flow/wastewater flow) is 0.25. The suspended solids concentration is assumed to be 2500 mg/L in the activated sludge tank. The over flow rate is 50 m3/d- m2 and solids loading is 125 kg/d-m2. Estimate detention time if the depth is 4.5 m. What would be the weir loading? Department of Civil & Environmental Engineering P.O. Box 519 Mail Stop 2510, Prairie View, Texas 77446 w.pvamu.edu Phone (936) 261-1660/1665(dept) Fax (936) 261 1662 Ensuring o Using Zoom o
6. After your flash mix the water was sent to a clarification basin that was 24 feet in diameter and 20 feet tall. What was the detention time in hours of 0.43 MGD? 5.4 hours 4.3 hours 3.8 hours 2.3 hours After the water leaves your sedimentation basin, it is ready for filtration. Your two filters measure 10 feet in diameter. What is the filtration rate is gpm for your flow of 0.43 MGD? 19 gpm/sq/ft 29 gpm/sq/ft 39 gpm/sq/ft 49 gpm/sq/ft You have had a filtration breakthrough (failure) and have brought your old roughing filtration system on line. The old filter is 8 feet square and 4 feet deep. What is the filtration rate in gpm/sq/ft for your flow of 0.43 MGD? 10.33 gpm/sq/ft 8.55 gpm/sq/ft 5.99 gpm/sq/ft 4.66 gpm/sq/ft