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Ex Design a colpitts oscillator to oscillate at 100 KHZ, use L= oilm H and the gain must be not exceed 10? solution f=d ZvJL - Сел Ceq = 25.35nf look = toct 25.35n=TICK 1 20T 50.1 x 10²³ Ceq ; A=10 and A- 54₂= How did he get the value inside the circle 25.35*11 10 ساس and G₁ = 10x 27.89 n = 0.278 uf = 27.89nf

Ex Design a colpitts oscillator to oscillate at 100 KHZ, use L= oilm H and the gain must be not exceed 10? solution f=d ZvJL - Сел Ceq = 25.35nf look = toct 25.35n=TICK 1 20T 50.1 x 10²³ Ceq ; A=10 and A- 54₂= How did he get the value inside the circle 25.35*11 10 ساس and G₁ = 10x 27.89 n = 0.278 uf = 27.89nf

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Ex Design a colpitts oscillator to oscillate at 100 KHZ, use L= oilm H and the gain must be not exceed 10? solution f=ZWJL Ca Ceq=25.35nf look = 1 2IT √0.1 x 10³ Ceg :) A=10 and A= C₂²₂ How did he get the value inside the circle Loca 25.35n=115 and G₁ = 10x27.89 n = 0.278 μ f 54₂= 25.35*11 10 27.89 nf
Transcribed Image Text:Ex Design a colpitts oscillator to oscillate at 100 KHZ, use L= oilm H and the gain must be not exceed 10? solution f=ZWJL Ca Ceq=25.35nf look = 1 2IT √0.1 x 10³ Ceg :) A=10 and A= C₂²₂ How did he get the value inside the circle Loca 25.35n=115 and G₁ = 10x27.89 n = 0.278 μ f 54₂= 25.35*11 10 27.89 nf
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