Ex 4-3: A transmitter transmits an AM/DSB single tone-modulating signal given by 3 cos(2n10³ t) volt with a carrier signal given by 10 cos(2n10°t) volt,Find: 1- Modulation depth. 2- USB & LSB frequencies. 3- Amplitude of sideband frequencies. 4- Efficiency of Transmission. (CH 4) Amplitude Modulation Solution: Am 3 v, Ac 10 v fm 10³ Hz, fe=106 Hz = 3 = X 10 1- D = × 100% 100% = 30% Am Ac 3- Amp. of USB & LSB is 2- USB frequency is fe + fm = 106 + 103 = 1.001 MHz, LSB frequency is fe- fm = 106-10³ = 0.999 MHz = 0.75 volt Ps m² 0.32 4- n = = Pt m² +2 0.3²+2 84 f(t) = By Dr. Hikmat Al-Shamary & Dr. Tariq M. Salman mAc 4 = 4.3% 0.3x10 4 H.W: Repeat the previous example assuming that the modulating signal is given by: 0

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Ex 4-3:
A transmitter transmits an AM/DSB single tone-modulating signal given by
3 cos (210³ t) volt with a carrier signal given by 10 cos(2 710ºt) volt,Find:
1- Modulation depth.
2- USB & LSB frequencies.
3- Amplitude of sideband frequencies.
4- Efficiency of Transmission.
(CH 4) Amplitude Modulation
Solution:
Am 3 v, A. 10 v
fm 10³ Hz, fc=106 Hz
3
1- D= Ame x 100% = x 100%
Ac
10
3- Amp. of USB & LSB is
30%
2- USB frequency is fe + fm = 106 + 10³ = 1.001 MHz,
LSB frequency is fc-fm = 106 - 10³ = 0.999 MHz
mAc
0.3x10
= 0.75 volt
Ps m² 0.3²
Pt m²+2 0.3²+2
4- n = =
H.W:
=
84
= 4.3 %
By Dr. Hikmat Al-Shamary & Dr. Tariq M. Salman
Repeat the previous example assuming that the modulating signal is given by:
0<t <2*10-³
2 * 10 3 < t <4*10-³
(t-1,
f(t) = {t 0,
Assume that the signal is band-limited to 1 kHz.
Repeats periodically
Transcribed Image Text:Ex 4-3: A transmitter transmits an AM/DSB single tone-modulating signal given by 3 cos (210³ t) volt with a carrier signal given by 10 cos(2 710ºt) volt,Find: 1- Modulation depth. 2- USB & LSB frequencies. 3- Amplitude of sideband frequencies. 4- Efficiency of Transmission. (CH 4) Amplitude Modulation Solution: Am 3 v, A. 10 v fm 10³ Hz, fc=106 Hz 3 1- D= Ame x 100% = x 100% Ac 10 3- Amp. of USB & LSB is 30% 2- USB frequency is fe + fm = 106 + 10³ = 1.001 MHz, LSB frequency is fc-fm = 106 - 10³ = 0.999 MHz mAc 0.3x10 = 0.75 volt Ps m² 0.3² Pt m²+2 0.3²+2 4- n = = H.W: = 84 = 4.3 % By Dr. Hikmat Al-Shamary & Dr. Tariq M. Salman Repeat the previous example assuming that the modulating signal is given by: 0<t <2*10-³ 2 * 10 3 < t <4*10-³ (t-1, f(t) = {t 0, Assume that the signal is band-limited to 1 kHz. Repeats periodically
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