ex = 1+ sin x = x COS X = - 1 - 38 3! х 1! + x2 + N8 x5 5! 2! - + 3! 28 7! x4 + 2! 4! (a) Write the Maclaurin series for 4! = 7 + = ∞ Σ(-1)". n=0 ปร n!' n=0 x²+1 (2n+1)!' + = 6! Σ(-1)" x2n (2n)!' n=0 x6 f(x) = cos x + sin x, (b) for ex - COS X - sin x 9(x) = x2 ex - f(x) x2 (c) and for | 9(x)dx = [ ex COS X - sin x -dx. x2
ex = 1+ sin x = x COS X = - 1 - 38 3! х 1! + x2 + N8 x5 5! 2! - + 3! 28 7! x4 + 2! 4! (a) Write the Maclaurin series for 4! = 7 + = ∞ Σ(-1)". n=0 ปร n!' n=0 x²+1 (2n+1)!' + = 6! Σ(-1)" x2n (2n)!' n=0 x6 f(x) = cos x + sin x, (b) for ex - COS X - sin x 9(x) = x2 ex - f(x) x2 (c) and for | 9(x)dx = [ ex COS X - sin x -dx. x2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:ex = 1+
sin x
= x
COS X =
-
1
-
38
3!
х
1!
+
x2
+
N8
x5
5!
2!
-
+
3!
28
7!
x4
+
2! 4!
(a) Write the Maclaurin series for
4!
=
7
+ =
∞
Σ(-1)".
n=0
ปร
n!'
n=0
x²+1
(2n+1)!'
+
=
6!
Σ(-1)"
x2n
(2n)!'
n=0
x6
f(x) = cos x + sin x,
(b) for
ex
-
COS X - sin x
9(x) =
x2
ex - f(x)
x2
(c) and for
| 9(x)dx = [
ex
COS X
- sin x
-dx.
x2
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