ex 1₁-0² (1 - e²x) a. 3 b. C. ex VI d. √1 G ex ex 3 2 5 ² ( + 2 1-e(2x) 2 5 dx e2x In 1-e2|+C e2 + C +C + C

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A: Above question is solved

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Q: у 3 2 1 -1- -2 -3 1 2 3 4 5 6 X

A: Here is the solution: