ever is flawed if a standard nut cannot be screwed onto the threads. Let p equal the proportion of flawed toggle evers that the shop manufactures. If there were 24 flawed evers out of a sample of 642 that were selected randomly from the production line, a) Give a point estimate of p. b) Use Equation 73-2 to find an approximate 95% confidence interval for p.
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- A sample of size 25 was taken from a very large population. Sample statistics, x¯ and s, were used to find that the 95% confidence interval was (138.616, 163.384). x¯= s=A sample of 100 shoppers chosen at random from all shoppers in a given province indicated that 55% of them preferred a particular store (Shoprite).i. Find a 95% confidence interval for the proportion of all the shoppers that preferred Shoprite.ii. How large a sample of shoppers should we take in order to be 95% confident that the shoppers will buy from Shoprite?if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
- Given two independent random samples with the following results: n₂ = 8 x₂ = 124 $2 = 28 = 16 n₁ x₁ = 94 $1 = 16 Use this data to find the 90 % confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval.5.A random sample of 362 married couples found that 286 had two or more personality preferences in common. In another random sample of 550 married couples, it was found that only 30 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. Find a 90% confidence interval for p1 – p2. (Use 3 decimal places.) lower limit upper limitA district official intends to use the mean of a random sample of 150 sixth graders from a very large school district to estimate the mean score that all the sixth graders in the district would get if they took a certain arithmetic achievement test. If, based on experience, the official knows that = 9.4 for such data, suppose that the district official takes her sample and gets = 61.8. Use all the given information to construct a 99% confidence interval for the mean score of all the sixth graders in the district.
- 4. The resilient moduli of 10 samples of a clay mixture are measured and the sample mean is x = 19.50. If an experimenter wishes to use a "known" value o = 1.0 for the standard deviation of the resilient modulus measurements based upon prior experience, construct appropriate 90%, 95%, and 99% two-sided confidence intervals for the average resilient modulus µ. Compare the lengths of the confidence intervals. Do you think it is plausible that the average resilient modulus is equal to 20.0?One company recently conducted a survey in which 420 women and 420 men were asked "Are you satisfied with the work of the Minister of Health?". Of these, 155 men and 118 women said they were satisfied with the minister's work. Assume that the experimental design was correct. Questions 1 and 2 cover this survey. 1. Find the upper limit of 95% confidence interval for the difference in the proportion of men and women who are happy with the work of the Minister (let men be group 1). 1. 0.03. 2. 0.09. 3. 0.15. 4. It is not possible to apply a normal approach and therefore we can not calculate the confidence interval. 2. What is the rejection area if it is to be examined whether the proportion of men and women who are satisfied with the job of Prime Minister is different (use a = 0.05)? 1. RejectHO efz 1.96. 2. Reject HO if z> 1.64. 3. RejectHO efz> -1.96 or <1.96. 4. Insufficient information provided to answer this.If n=�=25, ¯x=�¯=45, and s=�=6, find the margin of error E� at a 95% confidence level. Give your answer to at least two decimal places.
- tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation isQ.4.1 Construct a 99% confidence interval for the true proportion of all employees ofPeople Plus Pty who believe that they should be given a raise by the company,given that 115 out of a sample of 135 employees support this suggestion.Interpret your answer.2. Scored obtained by a large group of students taking a test are known to be normally distributed. A random sample of twenty-five students test scores yielded the following statistics: 25 と=1Xi 25 1508 x - 95628 Find a 95% confidence interval for the population mean.