I want to confirm if my answers are correct and if not, how would I approach this problem? Event A: The selected ball has an odd number on itEvent B: The selected ball is greyEvent A or B: The selected ball has an odd number on it or isgreyEvent A and B: The selected ball has an odd number on it and isgrey(b) Compute the following.68 08P(A) + P (B) - P(A and B):=85(c) Select the answer that makes the equation true.P(A) + P (B)-P(A and B)=P(A or B)XX1 2>?UU5Outcomes3 4 5>?>U6U78Probability>+100UUUm 10038+0048m 10038 Eight balls numbered 1 to 8 are placed in a bag.Some of the balls are grey and some are white.The balls numbered 3, 4, and 6 are grey. The balls numbered 1, 2, 5, 7, and 8 are white.A ball will be selected from the bag at random.The 8 possible outcomes are listed below.Note that each outcome has the same probability.12345678Complete parts (a) through (c). Write the probabilities as fractions.(a) Check the outcomes for each event below. Then, enter the probability of the event.

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Event A: The selected ball has an odd number on it Event B: The selected ball is grey Event A or B: The selected ball has an odd number on it or is grey Event A and B: The selected ball has an odd number on it and is grey (b) Compute the following. 08 5 6100 P(A) + P (B) − P(A and B) (c) Select the answer that makes the equation true. P(A)+P (B)-P(A and B)=P(A or B) 010 X 3 U U U ? x 5 > U > } ? U

Event A: The selected ball has an odd number on it Event B: The selected ball is grey Event A or B: The selected ball has an odd number on it or is grey Event A and B: The selected ball has an odd number on it and is grey (b) Compute the following. 08 5 6100 P(A) + P (B) − P(A and B) (c) Select the answer that makes the equation true. P(A)+P (B)-P(A and B)=P(A or B) 010 X 3 U U U ? x 5 > U > } ? U

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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