Evaluation:A. Explain free falling bodyB. Solve the following problems neatly:1. A stone is thrown vertically upward from the ground with a velocity of 15m/sec. One second later, another stone is thrown vertically upward with avelocity of 30 m/sec.a. When will the stones be at the same level? Ans. t = 1.4 secb. How far above the ground will the stones be at the same level? Ans S=11.4 mc. Determine the time the second stone travelled until the stones are atthe same level? Ans. t2 = 0.4 sec2. A stone is dropped from a balloon at an elevation of 300 m. Twoseconds later, another stone is projected vertically upward from theground with a velocity of 75 m/sec.a. When will the stones pass each other? Ans. t = 4.963 secb. Where will the stones pass each other from the ground? Ans. S =179.2 mc. Compute the time travelled by the stone from the ground until theypass each other. Ans. t2 = 2.96 sec3. A stone is thrown vertically into the air at a velocity of 60 m/sec. After 4seconds, another stone is thrown vertically into the air.a. Determine the time that the first ball has travelled in order to meet thesecond ball 120 m from the ground. Ans. t1 = 6.1 secb. Determine the time that the second ball has travelled in order to meett2 = 3.6 secthe first ball 120 m from the ground. Ans. t3 = 5.7 secc. What initial velocity must the second ball have in order to meet the firstball 120 m from the ground? Ans. V3 = 49 m/sec4. A stone is thrown vertically upward with an initial velocity of 3 m/secfrom the top of a tall building. The stone strikes the ground 4 second later.a. What is the maximum height reached by the stone above the building?Ans. S = 0.459 mb. What is the height of the building? Ans. H = 66.331 mc. What is the velocity of the stone as it strikes the ground? Ans. V =36.20 m/sec5. A ball is thrown vertically up from the ground with a velocity of 90m/sec. How long must one wait before dropping a second ball from the topof a tower 180 m high if the two balls are to pass each other 60m from thetop of the tower?Ans. t1 = 16.90 sec, t2 = 3.5 sec, t3 = 13.4 sec7

Name: Evaluation:A. Explain free falling bodyB. Solve the following problem
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Description: Evaluation:A. Explain free falling bodyB. Solve the following problems neatly:1. A stone is thrown vertically upward from the ground with a velocity of 15m/sec. One second later, another stone is thrown vertically upward with avelocity of 30 m/sec.a

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Evaluation: A. Explain free falling body B. Solve the following problems neatly: 1. A stone is thrown vertically upward from the ground with a velocity of 15 m/sec. One second later, another stone is thrown vertically upward with a velocity of 30 m/sec. a. When will the stones be at the same level? Ans. t = 1.4 sec b. How far above the ground will the stones be at the same level? Ans S =11.4 m c. Determine the time the second stone travelled until the stones are at the same level? Ans. t2 = 0.4 sec

Evaluation: A. Explain free falling body B. Solve the following problems neatly: 1. A stone is thrown vertically upward from the ground with a velocity of 15 m/sec. One second later, another stone is thrown vertically upward with a velocity of 30 m/sec. a. When will the stones be at the same level? Ans. t = 1.4 sec b. How far above the ground will the stones be at the same level? Ans S =11.4 m c. Determine the time the second stone travelled until the stones are at the same level? Ans. t2 = 0.4 sec

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

Topic Video

Question

Evaluation:
A. Explain free falling body
B. Solve the following problems neatly:
1. A stone is thrown vertically upward from the ground with a velocity of 15
m/sec. One second later, another stone is thrown vertically upward with a
velocity of 30 m/sec.
a. When will the stones be at the same level? Ans. t = 1.4 sec
b. How far above the ground will the stones be at the same level? Ans S
=11.4 m
c. Determine the time the second stone travelled until the stones are at
the same level? Ans. t2 = 0.4 sec
2. A stone is dropped from a balloon at an elevation of 300 m. Two
seconds later, another stone is projected vertically upward from the
ground with a velocity of 75 m/sec.
a. When will the stones pass each other? Ans. t = 4.963 sec
b. Where will the stones pass each other from the ground? Ans. S =
179.2 m
c. Compute the time travelled by the stone from the ground until they
pass each other. Ans. t2 = 2.96 sec
3. A stone is thrown vertically into the air at a velocity of 60 m/sec. After 4
seconds, another stone is thrown vertically into the air.
a. Determine the time that the first ball has travelled in order to meet the
second ball 120 m from the ground. Ans. t1 = 6.1 sec
b. Determine the time that the second ball has travelled in order to meet
t2 = 3.6 sec
the first ball 120 m from the ground. Ans. t3 = 5.7 sec
c. What initial velocity must the second ball have in order to meet the first
ball 120 m from the ground? Ans. V3 = 49 m/sec
4. A stone is thrown vertically upward with an initial velocity of 3 m/sec
from the top of a tall building. The stone strikes the ground 4 second later.
a. What is the maximum height reached by the stone above the building?
Ans. S = 0.459 m
b. What is the height of the building? Ans. H = 66.331 m
c. What is the velocity of the stone as it strikes the ground? Ans. V =
36.20 m/sec
5. A ball is thrown vertically up from the ground with a velocity of 90
m/sec. How long must one wait before dropping a second ball from the top
of a tower 180 m high if the two balls are to pass each other 60m from the
top of the tower?
Ans. t1 = 16.90 sec, t2 = 3.5 sec, t3 = 13.4 sec
7

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