Evaluate: √x(x - 5)dx Solution: √ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/ = f (x² - 5x) dx by distribution of property of equality = f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module +C₁-5 + C₂ by power rule = 5 +C₁-5- Where C₁ + C₂ 5 2x² 15x² 15 3 5 2 2 3 2 + C₂ = = C 25 + C or -xz -x² + C
Evaluate: √x(x - 5)dx Solution: √ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/ = f (x² - 5x) dx by distribution of property of equality = f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module +C₁-5 + C₂ by power rule = 5 +C₁-5- Where C₁ + C₂ 5 2x² 15x² 15 3 5 2 2 3 2 + C₂ = = C 25 + C or -xz -x² + C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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Question
find the error
![Evaluate: √x(x - 5)dx
Solution:
√ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/
= f (x² - 5x) dx by distribution of property of equality
= f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module
+C₁-5
+ C₂ by power rule
=
5
+C₁-5-
Where C₁ + C₂
5
2x² 15x²
25 15 3
2²-1²
5
2
+ C₂
3
2
= = C
+ C or -xz
-x² + C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6664d484-678c-47ab-8053-c7e9442bea5b%2F8377788c-fbd4-4c40-961d-e95828c2857c%2Fj4h4pif_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate: √x(x - 5)dx
Solution:
√ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/
= f (x² - 5x) dx by distribution of property of equality
= f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module
+C₁-5
+ C₂ by power rule
=
5
+C₁-5-
Where C₁ + C₂
5
2x² 15x²
25 15 3
2²-1²
5
2
+ C₂
3
2
= = C
+ C or -xz
-x² + C
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