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Evaluate using Trigonometric Substitution: dx c² –6x+5 None of the choices. Please refer to my solution. O væ? 6x + 5 + In |(x – 3 + Væ² – 6x + 5)| + C | x² 6x + 5 + 3 ln |3 (x – 3+ Vx² – 6x + 5)| + C x² 6x + 5 + 5 ln | (x – 3+ Va? – 6æ + 5)| + C -

Evaluate using Trigonometric Substitution: dx c² –6x+5 None of the choices. Please refer to my solution. O væ? 6x + 5 + In |(x – 3 + Væ² – 6x + 5)| + C | x² 6x + 5 + 3 ln |3 (x – 3+ Vx² – 6x + 5)| + C x² 6x + 5 + 5 ln | (x – 3+ Va? – 6æ + 5)| + C -

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Evaluate using Trigonometric Substitution: dx Vx2 –6x+5 None of the choices. Please refer to my solution. 6x + 5 + In |(x – 3 + vx? – 6x + 5)| + C - O Vx² 6x + 5 + 3 ln |5(x – 3+ Væ? бх + 5)| + С - 6x + 5 + 5 ln(x 3 + Vx? 6x + 5)| + C
Transcribed Image Text:Evaluate using Trigonometric Substitution: dx Vx2 –6x+5 None of the choices. Please refer to my solution. 6x + 5 + In |(x – 3 + vx? – 6x + 5)| + C - O Vx² 6x + 5 + 3 ln |5(x – 3+ Væ? бх + 5)| + С - 6x + 5 + 5 ln(x 3 + Vx? 6x + 5)| + C
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