Evaluate this function of z = cos x sin y; x = u – v, y= u² + v². Use chain - dz rule to find ди А. 2ucos (u – v) cos (u? + v²) – sin(u – v) sin(u² + v² ) - В. 2usin (u – v) cos (u² + v²) – cos(u – v) sin(u² + v²) COS - - С. 3ucos (u – v) cos (u? + v²) + sin(u – v) sin(u² + v² ) | D. 3usin (u – v) sin(u? + v²) + cos(u – v) sin(u² + v² ) -
Evaluate this function of z = cos x sin y; x = u – v, y= u² + v². Use chain - dz rule to find ди А. 2ucos (u – v) cos (u? + v²) – sin(u – v) sin(u² + v² ) - В. 2usin (u – v) cos (u² + v²) – cos(u – v) sin(u² + v²) COS - - С. 3ucos (u – v) cos (u? + v²) + sin(u – v) sin(u² + v² ) | D. 3usin (u – v) sin(u? + v²) + cos(u – v) sin(u² + v² ) -
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.5: Polar Coordinates
Problem 98E
Related questions
Question
![Evaluate this function of
z = cos x sin y; x = u – v, y = u? + v². Use chain
rule to find Oz
ди
А.
2ucos (u – v) cos (u? + v²) – sin(u – v) sin (u² + v²)
В.
2usin (u – v) cos (u? + v² ) – cos(u – v) sin(u² + v²)
-
-
-
С.
3ucos (u – v) cos (u? + v²) + sin(u – v) sin(u² + v² )
D.
3usin (u – v) sin(u? + v²) + cos(u – v) sin (u² + v²)
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F311a3bf4-ba69-4117-b6a8-e293c7704822%2Fa80c4810-ecde-4cd0-819d-b64b3907f0af%2Fmgslxvg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Evaluate this function of
z = cos x sin y; x = u – v, y = u? + v². Use chain
rule to find Oz
ди
А.
2ucos (u – v) cos (u? + v²) – sin(u – v) sin (u² + v²)
В.
2usin (u – v) cos (u? + v² ) – cos(u – v) sin(u² + v²)
-
-
-
С.
3ucos (u – v) cos (u? + v²) + sin(u – v) sin(u² + v² )
D.
3usin (u – v) sin(u? + v²) + cos(u – v) sin (u² + v²)
-
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