• Evaluate the surface integral s F dS where F= (3x, z,-y) and S is the part of the sphere x² + y²+z² = 9 in the first octant, with orientation toward the origin. A parametrization for S is 7(u, v) = (3 sin v cos u, 3 sin v sin u, 3 cos v) over the domain [0, 1] × [0, 1]. JJs F- ds =
• Evaluate the surface integral s F dS where F= (3x, z,-y) and S is the part of the sphere x² + y²+z² = 9 in the first octant, with orientation toward the origin. A parametrization for S is 7(u, v) = (3 sin v cos u, 3 sin v sin u, 3 cos v) over the domain [0, 1] × [0, 1]. JJs F- ds =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Evaluate the surface integral s F dS where F= (3x, z,-y) and S is the part of the sphere x² + y²+z² = 9 in the first octant, with orientation toward the
origin. A parametrization for S is 7(u, v) = (3 sin v cos u, 3 sin v sin u, 3 cos v) over the domain [0, 1] × [0, 1].
JJs F- ds =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F06f7b891-a6fe-4179-a0b4-110b5276bf5f%2Fb87764fc-e66f-40f9-9701-8d08908198f0%2Fgd2mj1s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:•
Evaluate the surface integral s F dS where F= (3x, z,-y) and S is the part of the sphere x² + y²+z² = 9 in the first octant, with orientation toward the
origin. A parametrization for S is 7(u, v) = (3 sin v cos u, 3 sin v sin u, 3 cos v) over the domain [0, 1] × [0, 1].
JJs F- ds =
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