Evaluate the surface integral positive (outward) orientation. IS² F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the F(x, y, z) = -xi - yj + z³k, S is the part of the cone z = 1712T 15 x² + y2 between the planes z = 1 and z = 3 with downward orientation
Evaluate the surface integral positive (outward) orientation. IS² F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the F(x, y, z) = -xi - yj + z³k, S is the part of the cone z = 1712T 15 x² + y2 between the planes z = 1 and z = 3 with downward orientation
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Evaluate the surface integral
positive (outward) orientation.
F(x, y, z) = -xi - yj + z³k, S is the part of the cone z = √√x² + y² between the planes z = 1 and z = 3 with downward orientation
1712T
15
SS²
F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39f6380b-55e3-47ff-8091-2f92e2b304db%2F64be5fec-a400-43ca-986d-937cafe52a33%2Fwdcgnjh_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate the surface integral
positive (outward) orientation.
F(x, y, z) = -xi - yj + z³k, S is the part of the cone z = √√x² + y² between the planes z = 1 and z = 3 with downward orientation
1712T
15
SS²
F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the
X
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