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Evaluate the surface integral F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = -xi-yj+z3k, S is the part of the cone z = √√x² + between the planes z = 1 and z = 2 with downward orientation 1 z=2

Evaluate the surface integral F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = -xi-yj+z3k, S is the part of the cone z = √√x² + between the planes z = 1 and z = 2 with downward orientation 1 z=2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Evaluate the surface integral F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = −xi - yj + z³k, S is the part of the cone z = x²+2 between the planes z = 1 and z = 2 with downward orientation ZA z = √√x²+ y² x z=2
Transcribed Image Text:Evaluate the surface integral F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = −xi - yj + z³k, S is the part of the cone z = x²+2 between the planes z = 1 and z = 2 with downward orientation ZA z = √√x²+ y² x z=2
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