Evaluate the surface integral F. ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = yi + xj + z²k, s is the helicoid (with upward orientation) with vector equation r(u, v) = u cos(v)i + u sin(v)j + vk, 0 ≤ u≤ 4,0 ≤ v ≤ 2π

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Q: 3/ MATH

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A: Introduction: The flux of the vector field F is given by the formula, ∮CF.ndS=∫∫∫div(F)dA

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