Evaluate the limits. lim 12= X-7 lim X->-1 lim (5+3)= +->5 X= lim (4₂³-3₂) = X-7-1 lim X-7 lim X-7-3 X3-1 X-1 x²+7x+12 X+ 3 Tim 7 - 12/31 4-73 Y-3

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A: See the answer below

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Q: 1. Evaluate each of the following: x3-64 a. lim X4x2-16 x-1 b. lim x-1 vx+3-2 1 1 C. lim 4 X→4ズー4

A: a)  limx→4 x3-64x2-16 = limx→4 x3-(4)3x2-42= limx→4 (x-4)(x2+4x+16)(x-4)(x+4)     ... Use (a3-b3) =…

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Q: 2. Evaluate lim (5x - 2 x+3.

A: To evaluate the limit: limx→∞5x-2x+3 Solution: We know that, limx→afx-gx=limx→afx-limx→agx Using the…