Evaluate the iterated integral [² [² 2e3² dy dx by changing the order of integration.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Evaluating Iterated Integrals: Changing the Order of Integration**

In this section, we will learn how to evaluate iterated integrals by altering the order of integration. We are given a specific example to illustrate this process.

### Problem

Evaluate the iterated integral:

\[ \int_{0}^{2} \int_{x}^{2} 2e^{y^2} \, dy \, dx \]

by changing the order of integration.

### Solution Outline

1. **Understand the Region of Integration**:
   - The inner integral \(\int_{x}^{2} 2e^{y^2} \, dy\) suggests that for a fixed \(x\), \(y\) ranges from \(x\) to 2.
   - For the outer integral, \(x\) ranges from 0 to 2.

2. **Sketch the Region**:
   - Draw the region in the \(xy\)-plane defined by \(0 \leq x \leq 2\) and \(x \leq y \leq 2\).

**Region Description**:
   - The region is bounded below by \(y = x\) and above by \(y = 2\), with \(x\) ranging from 0 to 2.

3. **Reverse the Order of Integration**:
   - Identify new bounds for \(x\) and \(y\) when switching the order.
   - \(y\) now ranges from 0 to 2.
   - For a fixed \(y\), \(x\) ranges from 0 to \(y\).

4. **Rewrite the Integral**:
   - The new integral is:
   \[ \int_{0}^{2} \int_{0}^{y} 2e^{y^2} \, dx \, dy \]

5. **Evaluate the New Integral**:
   - Integrate the inner integral with respect to \(x\):
     \[ \int_{0}^{y} 2e^{y^2} \, dx = 2e^{y^2} \times x \bigg|_{0}^{y} = 2ye^{y^2} \]

   - Integrate the result with respect to \(y\):
     \[ \int_{0}^{2} 2y e^{y^2} \, dy \]
     - Use substitution \(u
Transcribed Image Text:**Evaluating Iterated Integrals: Changing the Order of Integration** In this section, we will learn how to evaluate iterated integrals by altering the order of integration. We are given a specific example to illustrate this process. ### Problem Evaluate the iterated integral: \[ \int_{0}^{2} \int_{x}^{2} 2e^{y^2} \, dy \, dx \] by changing the order of integration. ### Solution Outline 1. **Understand the Region of Integration**: - The inner integral \(\int_{x}^{2} 2e^{y^2} \, dy\) suggests that for a fixed \(x\), \(y\) ranges from \(x\) to 2. - For the outer integral, \(x\) ranges from 0 to 2. 2. **Sketch the Region**: - Draw the region in the \(xy\)-plane defined by \(0 \leq x \leq 2\) and \(x \leq y \leq 2\). **Region Description**: - The region is bounded below by \(y = x\) and above by \(y = 2\), with \(x\) ranging from 0 to 2. 3. **Reverse the Order of Integration**: - Identify new bounds for \(x\) and \(y\) when switching the order. - \(y\) now ranges from 0 to 2. - For a fixed \(y\), \(x\) ranges from 0 to \(y\). 4. **Rewrite the Integral**: - The new integral is: \[ \int_{0}^{2} \int_{0}^{y} 2e^{y^2} \, dx \, dy \] 5. **Evaluate the New Integral**: - Integrate the inner integral with respect to \(x\): \[ \int_{0}^{y} 2e^{y^2} \, dx = 2e^{y^2} \times x \bigg|_{0}^{y} = 2ye^{y^2} \] - Integrate the result with respect to \(y\): \[ \int_{0}^{2} 2y e^{y^2} \, dy \] - Use substitution \(u
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