Evaluate the integrals: 1₁ = - S using Second-order Gauss quadrature. O I₁ = 3.1416 12 = 1.5708 1₁ = 3.1416 12 = 1.7671 1₁ 1 2.3856 12 = 2.9597 TC 2sin2 xdx and 1₂ = h 2π sin² x 0 -dx

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Evaluate the integrals:
1₁=
- S 2sin2 xdx and 12 =
using Second-order Gauss quadrature.
1₁ = 3.1416
12 = 1.5708
1₁ = 3.1416
12 1.7671
-
1₁ = 2.3856
12 = 2.9597
·2π
= √2²* sir
0
sin² x
2
-dx
Transcribed Image Text:Evaluate the integrals: 1₁= - S 2sin2 xdx and 12 = using Second-order Gauss quadrature. 1₁ = 3.1416 12 = 1.5708 1₁ = 3.1416 12 1.7671 - 1₁ = 2.3856 12 = 2.9597 ·2π = √2²* sir 0 sin² x 2 -dx
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