Hello, I am not too sure where I am going wrong on this trig sub integral. Attached is the question and my answer is cut off, but it is fully visibile in my work on the bottom of the page. Evaluate the integral. (Use C for the constant of integration.)x2sinV 3 + 2xXx2 dx407-04-4-12:− 1) (4 – (x− 1)²) ( ³ )(x−1)³√/4—(x−1)² _ __ 2(4− (x −1)²) (³)83+((x-1)-x =24/4S x²-√3+26-x² dx - (2²-24-3) » ((X²2x+1) -1-3)-(x-3) (x+¹) -((x-1)²-4)4/2²/14--1²U₁= X-1X=utlS (ONLY) ² 14-1² 1-2 smal√4-4SINE2√1-SIN²8Was-Wustdu= Lees &deS (RSING + 1)² 20060 (2016)de > Selsw²~ + 4sm²+1) (Yes²e)bloپر10√4-08-1²2U=X-14=c030dn=-Sab> Sple sm²³bres y + 10SING Les³6 + "les"Edb = [lbimi creas'E +16 | sinfecus be + 4Scas se ll16 5 4 (1-ci5 26) ( 2 (1+cs26)) - 16 Su²c + 45 = (1 + (526) E16 (2) S 1 - ₂ ( 1 + cos 46 ) - 16 Sui² du + 4 (3) S 1+ cos26d6145 de = { [Sdb + & Scusuda] - 16 Su²cdn + 25 d6 + 1 Seesuche4 [6 = { (6 + + sw46)] - 16[ 3 w²] + 2 [ @ + { sinize]146-26 = 25w1l6-16 205/6 + + SIN 26(펄4 SIN" (2²) - { (4) (²) (²SANG=X=11056 = √4-17-1²Z√4-(x-1)²B = S/~² ( (-¹)16/√√4-(x-1) ²2SIN 46 = 25 №26 COSZE234s (5)-2 (5) (-)-()) - ³16(4-(~1² (-1)-916(4-(x-1)})USIN82+4₁ (1) - (x-1) (4- (x-1)²) ²2 (8-1)²14-(x-1)² - 2 (4-(x-1) ²2 (x-1)/√4-76) +C传1+ 14248834SINIZE = 25=1020261-605/65 +4326-c03²26+ 2((5²) ( ¹4-12-0²4 F-5+1/2W42 (25640ss) ((US²4-4 (SINGLEssy-sures1-ces²26 → 1-1 (1+ (0540)

Evaluate the integral. (Use C for the constant of integration.) √x² √/3+2x - x² dx 46²2-1 (2-4) (x−1)(4—(x−1)²)(³) __ _(x−1)³√/4—(x−1)²__2(4-(x−1)²)(³) ₁ (x-1). sin - 4 + 8 3

Evaluate the integral. (Use C for the constant of integration.) √x² √/3+2x - x² dx 46²2-1 (2-4) (x−1)(4—(x−1)²)(³) __ _(x−1)³√/4—(x−1)²__2(4-(x−1)²)(³) ₁ (x-1). sin - 4 + 8 3

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Hello, I am not too sure where I am going wrong on this trig sub integral. Attached is the question and my answer is cut off, but it is fully visibile in my work on the bottom of the page.

Evaluate the integral. (Use C for the constant of integration.)
x2
sin
V 3 + 2x
X
x2 dx
407-04-4-12
:− 1) (4 – (x− 1)²) ( ³ )
(x−1)³√/4—(x−1)² _ __ 2(4− (x −1)²) (³)
8
3
+
(
(x-1)-
x

=
24/4S x²-√3+26-x² dx - (2²-24-3) » ((X²2x+1) -1-3)
-(x-3) (x+¹) -((x-1)²-4)
4/2²/14--1²
U₁= X-1
X=utl
S (ONLY) ² 14-1² 1-2 smal
√4-4SINE
2√1-SIN²8
Was-Wust
du= Lees &de
S (RSING + 1)² 20060 (2016)de > Selsw²~ + 4sm²+1) (Yes²e)blo
پر
10
√4-08-1²
2
U=X-1
4=c030dn=-Sab
> Sple sm²³bres y + 10SING Les³6 + "les"Edb = [lbimi creas'E +16 | sinfecus be + 4Scas se ll
16 5 4 (1-ci5 26) ( 2 (1+cs26)) - 16 Su²c + 45 = (1 + (526) E
16 (2) S 1 - ₂ ( 1 + cos 46 ) - 16 Sui² du + 4 (3) S 1+ cos26d6
145 de = { [Sdb + & Scusuda] - 16 Su²cdn + 25 d6 + 1 Seesuche
4 [6 = { (6 + + sw46)] - 16[ 3 w²] + 2 [ @ + { sinize]
146-26 = 25w1l6-16 205/6 + + SIN 26
(펄
4 SIN" (2²) - { (4) (²) (²
SANG=
X=1
1056 = √4-17-1²
Z
√4-(x-1)²
B = S/~² ( (-¹)
16/√√4-(x-1) ²
2
SIN 46 = 25 №26 COSZE
2
3
4s (5)-2 (5) (-)-()) - ³16(4-(~1² (-1)-9
16(4-(x-1)})
USIN
8
2
+4₁ (1) - (x-1) (4- (x-1)²) ²2 (8-1)²14-(x-1)² - 2 (4-(x-1) ²2 (x-1)/√4-76) +C
传
1+ 14
24
88
3
4
SINIZE = 25=102026
1-605/65 +4326-c03²26
+ 2((5²) ( ¹4-12-0²
4 F-5+1/2
W
42 (25640ss) ((US²4-
4 (SINGLEssy-sures
1-ces²26 → 1-1 (1+ (0540)

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