Evaluate the integral. (Use C for the constant of integration.) dx x² + 9 2+9 n(x+ Vx² + 9 ) +C ×

Q: Let a > 16 be a constant. Evaluate 42 + 40z + 68 + 2a dz (4x + a)(z² + 8x + 17)

A:

Q: integrate |8x2 x+7 dx 8xx+7 dx =| Vx+7dx

A:

Q: -3xdx 8. S: 2x+1

A: The given integral is; -3x/√(2x+1).

Q: 1- 3t - 2 t+1 - dt

A:

Q: f. S r4 dx J2 xV2-2x2 2.

A:

Q: x2 - 4 3 dx

A: The given integral is: I=∫x2-4x3dx

Q: 2 dx 8x + 9

A: To find the value of given integration  We use some basic results of integration and substitution

Q: 2x (i) da 1+z?

A:

Q: 7x2 + 15 dx. x2 + x Compute f

A:

Q: Evaluate 3 (9x² – 2x + 1)dx 1

A: Given:∫13 9x2-2x+1 dxIntegrating formula:∫xn dx=xn+1+C

Q: dx :Vx2 -1 1

A:

Q: 2 X 2 X 0+ - 4 +4 dx =

A: C+C

Q: x+1 3. Jx2 + 2x

A:

Q: Evaluate and simplify J 4-x2

A: Given : Indefinite integral ∫x24-x2dx   To find : Simplify and evaluate the given integral ?

Q: dx 2. Evaluate -2 v2x2 + 8x + 10

A:

Q: dx Vx4 – 2x² + 1 3,

A:

Q: Evaluate using integration by part technique. V3x +7

A:

Q: 3 ν1+ x2 χdx

A: ∫fxnf'xdx=fxn+1n+1,n≠-1

Q: 6х- 5 dx Vx2 - 12x +52

A: The fundamental use of integration is as a continuous version of summing. The extra C, is called the…