Can someone help me solve this problem with all steps included than you. Evaluate the integral:Hint: Integrate by parts.Olet u=x², du=2xdx, dv=cosxdx, v = sinx[x²cosxdx=x²sinx-- [2xsinxdx=x²sinx + 2cosx + Cx2sinx— -√2x5O let u=x², du=2xdx, dv=cosxdx, v= sinxS.x²cosxdx=x²sinx-let u=2x, du 2dx, dv=sinxdx, v= - cos.x=x²sinx+ 2xcos.x -rsinx—2xsinxdx=x²sinx-√2coO let u=x², du=2xdx, dv=cosxdx, v = sinx[x2²cosxdx=x²sinx- 2xsinxdxlet u=2x, du =2dx, dv-sinxdx, v=-cos.x=x²sinx + 2xcosx-fre-33[x²cosxdx=x² cos x dx.-f2xsinxdx:2xsinxdx=x²sinx- (-2xcos) - S-2002cosxdx√20-COS.X +2xsinxdx₁-[(- - 2xcos) --S-²2cosxdx=x²sinx + 2xcosx-2sinx + CO let u=x², du=2xdx, dv=cosxdx, v = sinx[x²cosxdx=x²³sinx-=x²sinx-2cosx + C-4Olet u = cosx, du = sinxdx, dv=x²dx, v=x³/3x3= --COST-1 = (-312-cosr+C2cosxdx=x²sinx + 2xcosx + 2sinx + C2xsinxdx2cosxdx(- sinx) dx

We have to evaluate the integral.

Evaluate the integral: Hint: Integrate by parts. Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx = x²sinx- =x²sinx + 2cosx + C x2sinx – =x²sinx + 2xcosx- -√21 Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx=x² 2sinx– √21 let u=2x, du = 2dx, dv=sinxdx, v = - cosx -f2vsinxdx= x2sinx – :-[2vsi 2xsinxdx fro 2xsinxdx=x²sinx-(-2xcos) - -√2co =x²sinx + 2xcos.x - -√2 x² cos x dx. 2xsinxdx Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx=x²-sinx- let u=2x, du=2dx, dv=sinxdx, v= - cosx [x²cosxdx=x²sinx- =x²sinx - 2cosx + C 2xsinxdx -[(-2veces) -/- 2cosite] 2cosxdx 2cosxdx=x²sinx + 2xcosx – 2sinx + C =x2sinx= 1-4 cost + — Cosr+C 12 2xsinxdx -[(-2vcos) - 1-2cc Olet u=x², du=2xdx, dv=cosxdx, v= sinx x-f2vsin 2cosxdx=x²sinx + 2xcosx + 2sinx + C xsin.xdx Olet u=cosx, du= - sinxdx, dv=x²dx, v=x³/3 +3 [x²cosxdx= -—-cost-/=/(- x3 3 3 2cosxdx (- sinx) dx

Evaluate the integral: Hint: Integrate by parts. Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx = x²sinx- =x²sinx + 2cosx + C x2sinx – =x²sinx + 2xcosx- -√21 Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx=x² 2sinx– √21 let u=2x, du = 2dx, dv=sinxdx, v = - cosx -f2vsinxdx= x2sinx – :-[2vsi 2xsinxdx fro 2xsinxdx=x²sinx-(-2xcos) - -√2co =x²sinx + 2xcos.x - -√2 x² cos x dx. 2xsinxdx Olet u=x², du=2xdx, dv=cosxdx, v= sinx [x²cosxdx=x²-sinx- let u=2x, du=2dx, dv=sinxdx, v= - cosx [x²cosxdx=x²sinx- =x²sinx - 2cosx + C 2xsinxdx -[(-2veces) -/- 2cosite] 2cosxdx 2cosxdx=x²sinx + 2xcosx – 2sinx + C =x2sinx= 1-4 cost + — Cosr+C 12 2xsinxdx -[(-2vcos) - 1-2cc Olet u=x², du=2xdx, dv=cosxdx, v= sinx x-f2vsin 2cosxdx=x²sinx + 2xcosx + 2sinx + C xsin.xdx Olet u=cosx, du= - sinxdx, dv=x²dx, v=x³/3 +3 [x²cosxdx= -—-cost-/=/(- x3 3 3 2cosxdx (- sinx) dx

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.2: Exponents And Radicals

Problem 20E

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