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Evaluate the indefinite integrals using Substitution. (use C for the constant of integration.) a) [ 3x²³(x³ - 2) ¹ dx = b) (2x + 9)(x² + 9x − 4)³ dx : = c) [x(x² − 9) ³ dx = -

Evaluate the indefinite integrals using Substitution. (use C for the constant of integration.) a) [ 3x²³(x³ - 2) ¹ dx = b) (2x + 9)(x² + 9x − 4)³ dx : = c) [x(x² − 9) ³ dx = -

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Evaluate the indefinite integrals using Substitution. (use C for the constant of integration.) a) [ 3x²(x²³ − 2) ¹ dx = / ›) (2x +9)(x² + 9x − 4)³ dx = - c) √ x(x² − 9)³ dx = d) = (28x + 4)(7x² + 2x − 8) ª dx (28
Transcribed Image Text:Evaluate the indefinite integrals using Substitution. (use C for the constant of integration.) a) [ 3x²(x²³ − 2) ¹ dx = / ›) (2x +9)(x² + 9x − 4)³ dx = - c) √ x(x² − 9)³ dx = d) = (28x + 4)(7x² + 2x − 8) ª dx (28
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