Evaluate the given expression and express the result using the usual format for writing numbers (instead of scientific notation). 30 C3 30 C3 =

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### Combinatorics Evaluation

**Problem Statement:**
Evaluate the given expression and express the result using the usual format for writing numbers (instead of scientific notation).

**Given Expression:**
\[ ^{30}C_{3} \]

**Question:**
Calculate \(^{30}C_{3}\)

**Answer:**
\[^{30}C_{3} = \boxed{} \]

### Explanation:

The given problem is a combinatorics problem where we need to calculate the number of ways to choose 3 items from a set of 30 items.

\[ ^{30}C_{3} \] represents a combination, which can be calculated using the formula:

\[ ^{n}C_{r} = \frac{n!}{r!(n-r)!} \]

For this particular problem:

\[ n = 30 \]
\[ r = 3 \]

Therefore:

\[ ^{30}C_{3} = \frac{30!}{3!(30-3)!} = \frac{30!}{3! \cdot 27!} \]

Next, simplify the factorials:

\[ 30! = 30 \times 29 \times 28 \times 27! \]

So:

\[ \frac{30!}{3! \cdot 27!} = \frac{30 \times 29 \times 28 \times 27!}{3! \times 27!} = \frac{30 \times 29 \times 28}{3!} \]

Since \( 3! = 6 \):

\[ ^{30}C_{3} = \frac{30 \times 29 \times 28}{6} \]

Calculating the values:

\[ 30 \times 29 = 870 \]
\[ 870 \times 28 = 24360 \]

Finally, divide by 6:

\[ \frac{24360}{6} = 4060 \]

So, the answer is:

\[ ^{30}C_{3} = \boxed{4060} \]
Transcribed Image Text:### Combinatorics Evaluation **Problem Statement:** Evaluate the given expression and express the result using the usual format for writing numbers (instead of scientific notation). **Given Expression:** \[ ^{30}C_{3} \] **Question:** Calculate \(^{30}C_{3}\) **Answer:** \[^{30}C_{3} = \boxed{} \] ### Explanation: The given problem is a combinatorics problem where we need to calculate the number of ways to choose 3 items from a set of 30 items. \[ ^{30}C_{3} \] represents a combination, which can be calculated using the formula: \[ ^{n}C_{r} = \frac{n!}{r!(n-r)!} \] For this particular problem: \[ n = 30 \] \[ r = 3 \] Therefore: \[ ^{30}C_{3} = \frac{30!}{3!(30-3)!} = \frac{30!}{3! \cdot 27!} \] Next, simplify the factorials: \[ 30! = 30 \times 29 \times 28 \times 27! \] So: \[ \frac{30!}{3! \cdot 27!} = \frac{30 \times 29 \times 28 \times 27!}{3! \times 27!} = \frac{30 \times 29 \times 28}{3!} \] Since \( 3! = 6 \): \[ ^{30}C_{3} = \frac{30 \times 29 \times 28}{6} \] Calculating the values: \[ 30 \times 29 = 870 \] \[ 870 \times 28 = 24360 \] Finally, divide by 6: \[ \frac{24360}{6} = 4060 \] So, the answer is: \[ ^{30}C_{3} = \boxed{4060} \]
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