Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Evaluate the function below at \( x = 14 \).**
\[
f(x) = \begin{cases}
-\frac{x}{6} + 7, & x \geq -10 \\
(x + 3)^2, & x < -10
\end{cases}
\]
This piecewise function is defined differently based on the value of \( x \). For \( x \geq -10 \), the function follows the rule \( -\frac{x}{6} + 7 \). For \( x < -10 \), the rule is \( (x + 3)^2 \). To find \( f(14) \), use the appropriate rule by substituting 14 into the function for \( x \geq -10 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8760b37b-3cc2-4bc5-bc8f-28ad60623677%2F9d25f9c5-707c-4860-89ec-52a0816aaa61%2Femzxrh_processed.png&w=3840&q=75)
Transcribed Image Text:**Evaluate the function below at \( x = 14 \).**
\[
f(x) = \begin{cases}
-\frac{x}{6} + 7, & x \geq -10 \\
(x + 3)^2, & x < -10
\end{cases}
\]
This piecewise function is defined differently based on the value of \( x \). For \( x \geq -10 \), the function follows the rule \( -\frac{x}{6} + 7 \). For \( x < -10 \), the rule is \( (x + 3)^2 \). To find \( f(14) \), use the appropriate rule by substituting 14 into the function for \( x \geq -10 \).
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