Evaluate the following integral between x=0 and x=7: 8x + x dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Question 2
3 pts
Evaluate the following integral between x=0
and x=7:
8х + x dx
Transcribed Image Text:Question 2 3 pts Evaluate the following integral between x=0 and x=7: 8х + x dx
Expert Solution
Step 1

Given

8x3+x dx

Find : The value of the given integral between x=0 and x=7

Consider, 078x3+x dx

078x3+x dx = 807x3 dx+07x dx

By using the formula xn dx =xn+1n+1, we get

078x3+x dx = 8x3+13+!07+x1+11+!07

                       = 8x4407+x2207

Applying the limit values , we get

                        = 874-04+72-02

                         =2(2401)+492

                         = 4802+492

                         = 2(4802)+492

                         = 96532

                         = 4826.5

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