Evaluate the following complex expressions. Present your answers in the trigonometric orm. Box your final answers. No. 1. In In e/150 j-4 4 (4cis) log3+j54 –, + In(-i) + (5,35°)* j6, )4- (2 - j5) 3 4 123 V = log 4-j 315 In log 5- j3- jlog(-7) | No. 2. X = principal root of no. 1; Y = second root of no. 1; and Z= third root of no. 1 Let: S (4 + jZ)e+ loge 3-15 [(3 + j4)3]°" 13-j7 (3 + j4)3 (Y – j'). (4/3) + In? In(jn) – j4(X + j7)m(- |
Evaluate the following complex expressions. Present your answers in the trigonometric orm. Box your final answers. No. 1. In In e/150 j-4 4 (4cis) log3+j54 –, + In(-i) + (5,35°)* j6, )4- (2 - j5) 3 4 123 V = log 4-j 315 In log 5- j3- jlog(-7) | No. 2. X = principal root of no. 1; Y = second root of no. 1; and Z= third root of no. 1 Let: S (4 + jZ)e+ loge 3-15 [(3 + j4)3]°" 13-j7 (3 + j4)3 (Y – j'). (4/3) + In? In(jn) – j4(X + j7)m(- |
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
3
![Evaluate the following complex expressions. Present your answers in the trigonometric
form. Box your final answers.
No. 1.
In In ej15°
j-4
4
(Acis ) log,.js 4 = j6 _ (2 – 15)“-/)
(2 - j5)
123
In(-i) + (5,35°)*
V =
log 4-
3 115
In
*log 5 – j3- jlog(-7)
No. 2.
X = principal root of no. 1;
Y = second root of no. 1; and
Z= third root of no. 1
Let:
loge 3-15 [(3 + j4)3]-"
(Y – j") ]
(4/3) + In?In(jn) – j4(X + j7)n(-4)
X
(4 + jZ)e* +
I =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdce8f65f-6b59-4ff9-b6c8-f51251924a92%2Fc05e6253-4ff6-4512-9578-cf6c192c133d%2Fl9azre9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Evaluate the following complex expressions. Present your answers in the trigonometric
form. Box your final answers.
No. 1.
In In ej15°
j-4
4
(Acis ) log,.js 4 = j6 _ (2 – 15)“-/)
(2 - j5)
123
In(-i) + (5,35°)*
V =
log 4-
3 115
In
*log 5 – j3- jlog(-7)
No. 2.
X = principal root of no. 1;
Y = second root of no. 1; and
Z= third root of no. 1
Let:
loge 3-15 [(3 + j4)3]-"
(Y – j") ]
(4/3) + In?In(jn) – j4(X + j7)n(-4)
X
(4 + jZ)e* +
I =
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