Evaluate the double integral 6y = 1/₂ (2² + 1) ² D I = when D is the region dady {(x, y): 0≤x≤1, 0≤ y ≤ √= } in the xy-plane. O O C O 1. I = 2. I = 3. I = 3 2 6 In 2 6. I = 3. 4. I = 3 5. I 3 ln 2 In 2 3 4
Evaluate the double integral 6y = 1/₂ (2² + 1) ² D I = when D is the region dady {(x, y): 0≤x≤1, 0≤ y ≤ √= } in the xy-plane. O O C O 1. I = 2. I = 3. I = 3 2 6 In 2 6. I = 3. 4. I = 3 5. I 3 ln 2 In 2 3 4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Evaluate the double integral**
\[ I = \int \int_D \frac{6y}{(x^2 + 1)^2} \, dx \, dy \]
when \( D \) is the region
\[ \{ (x, y) : 0 \leq x \leq 1, \quad 0 \leq y \leq \sqrt{x} \} \]
in the \( xy \)-plane.
---
**Options:**
1. \( I = \frac{3}{2} \)
2. \( I = 6 \ln 2 \)
3. \( I = \frac{3}{2} \ln 2 \)
4. \( I = 3 \)
5. \( I = 3 \ln 2 \)
6. \( I = \frac{3}{4} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84619d7f-a233-4879-b36c-9fd7a9106e23%2F4a615e81-936d-4c3b-bd8a-22d9d73ee4cc%2F87r6ug_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Evaluate the double integral**
\[ I = \int \int_D \frac{6y}{(x^2 + 1)^2} \, dx \, dy \]
when \( D \) is the region
\[ \{ (x, y) : 0 \leq x \leq 1, \quad 0 \leq y \leq \sqrt{x} \} \]
in the \( xy \)-plane.
---
**Options:**
1. \( I = \frac{3}{2} \)
2. \( I = 6 \ln 2 \)
3. \( I = \frac{3}{2} \ln 2 \)
4. \( I = 3 \)
5. \( I = 3 \ln 2 \)
6. \( I = \frac{3}{4} \)
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