Evaluate the definite integral by expressing it in terms of u and evaluating the resulting integral using a formula from geometry. sin 0V36 – 144 cos? 0 d0; u = 12 cos e NOTE: Enter the exact answer. sin 0V36 – 144 cos? 0 do =
Evaluate the definite integral by expressing it in terms of u and evaluating the resulting integral using a formula from geometry. sin 0V36 – 144 cos? 0 d0; u = 12 cos e NOTE: Enter the exact answer. sin 0V36 – 144 cos? 0 do =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 70E
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Evaluate the definite integral by expressing it in terms of u and
evaluating the resulting integral using a formula from geometry.
sin 0V36 – 144 cos? 0 d0;
u = 12 cos 0
NOTE: Enter the exact answer.
5m
sin 0V36 – 144 cos? 0 d0 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F76e5f829-f55d-4dd1-98ce-d270e46d25ec%2F8dbfca4f-473e-40f0-a0f6-70648126b26d%2Fk60nytl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 4 of 12
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Current Attempt in Progress
Evaluate the definite integral by expressing it in terms of u and
evaluating the resulting integral using a formula from geometry.
sin 0V36 – 144 cos? 0 d0;
u = 12 cos 0
NOTE: Enter the exact answer.
5m
sin 0V36 – 144 cos? 0 d0 =
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