Evaluate * | (0² + 1) cos 0 d0. e2sine + 20cose – sine + c 02sine – 20cos0 – sine + c Option 1 Option 2 -02sine – 20cose + sin® + c 02sino – 20cos0 + sin0 + c Option 4 Option 3

Q: Cos20=2Cos 0-1

A: Part 1,Given,            cos2θ=2cos2θ-1

Q: 1+cos2x 3. cotx sin 2x

A:

Q: Find the value of x  sin2x=sin600cos300-cos600sin300

A: Given,           sin2x=sin60°cos30°-cos60°sin30°

Q: sec(-0) cose 1-cos²0 csc20 CS

A:

Q: Is Cscx-1/1-Sinx=cscx

A:

Q: COSX cosx 10. 1-sinx 1+sinx

A:

Q: *cosx= 24 sinxyo, cos (x+5") 25

A: Given: cosα=2425, sinα>0 To determine: cosα+5π6

Q: Rewrite sin^2θcos^2θ in a way that does not use exponents and sinθ doesn't appear

A:

Q: Use the cofunction identities to select the correct answer which fills in the blank. cos(10x) = sin_…

A: We know that, sin(90°+x) = cos(x) sin(90°-x) = cos(x)