Evaluate for all angles of in the interval 0° ≤ 0 < 360º satisfy 5 sin (0) - 2 = 0 In which quadrants do the solutions exist (select two)? O Quadrant 1 O Quadrant 4 Quadrant 2 Give all angles below in degrees. 1st solution (lowest angle) O Quadrant 3 Round your answer to 2 decimal places. 2nd solution (highest angle) Round your answer to 2 decimal places.

Q: The point (-0.45, 0.89) lies on the unit circle. Which is the following expressions could be used to…

A: The coordinates  (−0.45,0.89)are lying on a unit circle Here we have to find which option defines…

Q: d) x=√3₁ It is given that sin x=- where x= [0,2], which quadrant(s) is x in?

A: We can answer both the question in the following steps.

Q: A+B+C = 180° then Sin At SinB+ Sin C = cotA cot B Sin A+ SinB Sin C 2. show that.

A:

Q: 4. Simplify, using the double-angle formulas: 1-2 sin² (15⁰)

A:

Q: c. sin? 0 -2cos? 0 = 0 over [0°, 360°)

A:

Q: Which values of x in the interval 0° sx < 360° satisfy the equation 2 sin?x+ sinx - 1 = 0? Select…

A: Given:      2sin2x+sinx−1=0

Q: Find all solutions of the equation in the interval [0, 2n). sin’x+4 sin x+ 3=0 Writ cwor in radianc…

A: we have equation,          sin2x + 4sinx + 3=0 we put sinx = x, we get          x2 + 4x +3 =0 we…

Q: 9cosx - 3 = 2 sin²x Over the interval [0, 2tr)

A: Convert the given equation in quadratic equation by using trigonometric formulas than solve it.