Evaluate dx Vx+2

Q: Find the domain of * y = V2x +12 ?

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Q: tanx V3+ts

A: According to the Leibniz rule, we have: ddx∫u(x)v(x)f(t)dt=f(v(x))·ddx[v(x)]-f(u(x))·ddx[u(x)]

Q: dx Vx² +9x² (In x³ )° 2

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Q: S(x*-3x3 +- -2)dx = x(8x*-30x3+5x-80) + C 1 %3D 40

A: Consider the right hand side of the given equation. The integration formula is  ∫xn=xn+1n+1+c

Q: Evaluate S (2x+3) dx x² (x²+1)

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Q: 2 3 Sźcsc(ln[5x²])cot(In[5x²])/csc(In[5x²]) + 5dx

A: To evaluate the following integral. ∫27x cscln5x2 cotln5x2 cscln5x2+53 dx

Q: dx Vx -9

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Q: 5x5 – 6xª + 2x³ – 29x² – 12x + 20 dx - - x²(x2 – 1)(x² + 4)

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Q: x + ax – 2bx - 2ab – x - 2ax - 2bx dx x* + ax? – 2bx² – 2abx?

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Q: -dx 2x3/2 — Зх2

A: Given : ∫x2x32-3x2dx ∫x2x32-3x2dx = -∫x3x2-2x32dx Now, let us solve ∫x3x2-2x32dx Let us take  u=x⇒…

Q: b8 xFx+T dx

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Q: Evaluate 4x2 + 4x + 5 dx

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Q: Find + 3x*) dx 3 3 + C

A: Integral.

Q: 1 dx 3x (3-9x)

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Q: SX³V1+ 4x2 dx .3

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Q: 12x+x² 2.

A: Given that, ∫dx2x+x2   As we know, 1+tan2x=sec2x ddxsecx=secxtanx ∫secxdx=ln|tan(x)+sec(x)|+C

Q: dx S x-Vx2+1

A: Given that, ∫1x2x2+1dx

Q: Differentiate y = (9x - 1)³. y = 8/9x - 9+

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Q: V9 – 4x2 dx

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Q: dx Find +8x + 12 x+ 8x + 12

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Q: IT 5tan(3x) dx 12

A: Given ∫π12π95tan(3x) dx