Evaluate [²³6²³² y dydadz

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Triple Integral Evaluation:**

Evaluate the integral:

\[
\int_{0}^{3} \int_{0}^{\frac{z}{3}} \int_{0}^{\sqrt{z^2 - x^2}} y \, dy \, dx \, dz
\]

This problem involves calculating a triple integral over a specified region. The limits of integration suggest a specific volume in a three-dimensional space bounded by the surfaces:

- \(z\) ranges from 0 to 3.
- \(x\) varies from 0 to \(\frac{z}{3}\).
- \(y\) ranges from 0 to \(\sqrt{z^2 - x^2}\).

The innermost integral is with respect to \(y\), integrated from 0 to \(\sqrt{z^2 - x^2}\). The middle integral is with respect to \(x\), and the outermost integral is with respect to \(z\). These limits describe a region in the \(xyz\)-coordinate system, which may need a geometric understanding to visualize the integration domain accurately.
Transcribed Image Text:**Triple Integral Evaluation:** Evaluate the integral: \[ \int_{0}^{3} \int_{0}^{\frac{z}{3}} \int_{0}^{\sqrt{z^2 - x^2}} y \, dy \, dx \, dz \] This problem involves calculating a triple integral over a specified region. The limits of integration suggest a specific volume in a three-dimensional space bounded by the surfaces: - \(z\) ranges from 0 to 3. - \(x\) varies from 0 to \(\frac{z}{3}\). - \(y\) ranges from 0 to \(\sqrt{z^2 - x^2}\). The innermost integral is with respect to \(y\), integrated from 0 to \(\sqrt{z^2 - x^2}\). The middle integral is with respect to \(x\), and the outermost integral is with respect to \(z\). These limits describe a region in the \(xyz\)-coordinate system, which may need a geometric understanding to visualize the integration domain accurately.
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