no 3 and 4 only using f(z) conjugate evalinaite the folling inegration, fulliming difPath cI'mpathzPathapath!Re(3,-2)pasth3| fc2)=f(2) dz whereRoes fle) matchCand - Riemani ZgPath I1け osオ+ I3 C = Path 23+ 3ost + Isintオー。4 C = Path 33す last。た。® now, flz) becomes f(2)=calcü late3oncinjugate

Note:- For part (3) it is not clear that the term written with sint (or coefficient of sint ) is "I"…

Answered: evalnante the folobwing…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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4)
Transformation of ₂F, If \x|< 1 and 2 Fi (a, b; c; x) = (1 − x)¯¨“, F₁ (a₁c-bic: == 1) a, c; X - X < 1; then:
That f(x) = -2x, g(x)= |x + 4|, and h(x)2/x-3. Evalute the functions for the given values of x: a)(g º f)(x) b)(g º f º h)(3) c)f(7)
Determine the function image
The product of x* + x3 + 2x? and 2x² + 4x + 6 in z, [x]/ is:
(4c) Prove that there exists no real number x such that x6 + x4 – 2x2 + 1 = 0
a) (-1,6)b) [-1,6]c) (-1,6]d) [-1,6) What is right here
Problem YOUDEN RECTANGLE'S PROBLEM BIBD- Balanced Incomplete Block Design . There is a matrix m x n. This matrix can be 26 x 4 but we can change this dimension if 26 x 4 does not admit a feasible solution. • m> n + 1 • The rows are called "blocks" and the columns are called "forms" • Every form is composed by the same number of blocks • • Every block is composed by the same number of forms The matrix is full and every single spot should be filled with a treatment Every treatment is is replicated r times in the Youden rectangle • Every treatment appears in every form maximum one time • Every couple of treatment appear together in every form 1 times Every treatment appear in all single blocks the same number of times v = number of treatments (1,2,3,4,.....,n) n = blocks (columns) m = forms (rows) r = number of times every treatment is replicated λ = number of times two treatment appear together in the same form Constraints: 1) nxm=vxr - 2) 1 (v 1) = r (k-1) 3) m > v then r > n Goal The…
2) Evaluate [sec² (x-4) do 3
b) The polynomial, fW) =2x" +mz -3, where m and n are real constants, is divisible by (x+1) but leaves a femiAder remainder of 156 when divided by (X-3). Find the valves of n and m.

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evalnante the folobwing integrationollowing a fferent Path C I'm troid.cpathz pathi Re (3,-2) path3