evalieante the folliwing innegratin ni fullowing dif Path C I'm 2 fo,1). (3,!) -3 -2 -1' pathz path! Re (3,-2) path3 | f(2) dz where f12)= O. Does fl2) match Cauchy, - Riemami Zgas C = path I け cosオ + ISint. オニ。 Lith 2 3+3 3+ las A +. I Si4 t ® now, flz) becomes fle)= repeit calcu late cinjugatie

Q: bijection

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Q: be the map O Let f Sending cach Complex number

A: The detailed solution is as follows below :

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Q: Prof the same for f(z) conjugate.

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A: Find all non-negative integer pairs of (x, y) such that .

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Q: Evaluate the complex numbers j(3 – j4)* (-1+ j6)(2 + j)² (a) z1 1 +j 4 – j8 11/2 (b) Z2

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Q: 17. Let f(x, y) = x'y4. Use Eq. (4) to estimate the change Af = f(2.03,0.9) – f(2, 1)

A: You have to just put the value in the function and proceed....go through the solution

Q: . Consider f(2)= (+ i)¹/3. Choose a set of branch cut (s) and sketch it in the complex plane. For…

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Q: evalicante the folining inregratio n , falliwing diffoit PathC Im to.). (3,!), parhz Pathe Re (3,-2)…

A: The given problem is to evaluate the complex integral over the given path z= 3+cos(t)+i sin(t) for t…

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A: First we will calculate Jacobian matrix at the origin and then its eigenvalues. Then depending on…

Q: +(x-1)+(x-1)+qy-2)+ Expanding Equation (3) and simplifying, we obtain the following equation…

A: Equation (3):We have to prove equation (4) which is:Formula used:here, , and .Therefore,

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Q: 3x +1 III.(10) Prove that the function f: R – {5} –> R – {3} defined by f(x) = is a bijection. x- 5

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Q: Determine the most possible complex zeros of the following function: f(x) = 3x¹ + 6x¹4 - 7x¹5 + 13x…

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