E°(V)1.23Calculate AG for the following reaction:4 Fe2+ (aq) +O2(g) +4 H+ (aq) →4 Fe3+ (aq) +2 H₂O(1)Express your answer using two significant figures.AG=-177.56 kJStandard Electrode Potentials at 25°CReduction Half-ReactionO2(g) +4 H+ (aq) + 4e → 2 H2O(1)Fe3+ (aq) + eFe²+(aq)PbO2 (s) + 4 H+ (aq) + 2e → Pb2+ (aq) + 2 H2O(l) 1.460.77SubmitPrevious AnswersCompletedPart BCalculate K for the following reaction:4 Fe²+(aq) +O2(g) +4 H+ (aq) → 4 Fe3+ (aq) +2 H2O(1)Express your answer using two significant figures.K=ΜΕ ΑΣΦSubmitRequest AnswerPart C?Calculate AG for the following reaction:2 PbO2 (s) + 4 H+ (aq) → 2 Pb2+ (aq) + O2(g) + 2 H2O(l)Express your answer using two significant figures

Part A:Step 1. Identify the half-reactions and their potentials:Reduction half-reaction: O2(g)+…

Answered: E°(V) 1.23 Calculate AG for the…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Reduction potential of Mg2+ is -2.37 V. Reduction Potential of Fe2+ is 0.44 V. Based on the reaction below what is the electrical energy? Mg(s) + Fe2+(aq) + Fe(s) Fe2+(aq) = 0.18 M ; Mg2+(aq) = 0.53M
What is AG" for the following reaction? Use data given in the table. 2Br (ag) + Cla (g) -→ Bra (1) + 2C1 (ag) Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°C Cathode (Reduction) Standard Half-Reaction Potential, E (V) Lit (ag) + e Li(s) Na+(ag) + e Na(s) Mg+ (ag) + 2e Mg(s) -3.04 -2.71 -2.38 Al* (ag) + 3e - Al(s) -1.66 2H20(1) + 2e H2(9) + 20H (ag) -0.83 Zn+ (ag) + 2e Zn(s) -0.76 Cr** (aq) + 3e Cr(s) --0.74 Fe+ (ag) + 2e Fe(s) -0.41 Ca2+ (aq) + 2e Cd(s) -0.40 Ni* (ag) + 2e Ni(s) -0.23 Sn* (aq) + 2e Sn(s) -0.14 Pb+ (ag) + 2e = Pb(s) --0.13 Fe* (ag) + 3e Fe(s) 2H* (ag) + 2e H2 (9) -0.04 0.00 Sn+ (ag) + 2e Sn+ (ag) 0.15
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy for the following redox reaction. Round your answer to 3 significant digits. The final units should be in kj
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Standard Electrode Potentials at 25 °C Reduction Half-Reaction O Cu (aq) O H,Ozlaq) O Br O 10₂ (aq) Fyl) +20 H₂O₂(aq) + 2 H(aq) +2e" PbOg(s) +4 H(aq) +50, (aq) + 2 e Mn0 (aq) +4 H(aq) + 3 e MnO, (aq) +8H(aq) + 5 e Au³(aq) + 3 e PbOy(s) +4 H(aq) + 2e¯ C+20 00, (aq) +14 H(aq) + 6 e 00+ 4H*(aq) + 4 MnO₂ (s) +4 H(aq) +2e¯ 10₂(aq) + 6H(aq) +5e Big(0+20 VO₂ (aq) + 2 H(aq) + e¯ NO₂ (aq) + 4H(aq) + 3 e CO₂(0)+ Ag (ag)+e Fe(aq) + e 0)+2 H(aq) +2 e Mn0, (aq) + e (8) +26 Cu (aq) + e -2 (aq) -2 H₂O(0) Which of the following is the strongest oxidizing agent? -PbSO4(s) + 2 H₂O(0) →→MnO₂ (s) + 2 H₂O(0) Mn²(aq) + 4H₂O(1) - Au(s) ·Pb²+ (aq) + 2 H₂O(0) - 2 Cr (aq) 2 Cr³+ (aq) + 7 H₂O(1) → 2 H₂O( -2(aq) -Cu(s) Mn²+ (aq) + 2 H₂O(0) ₂(aq) + 3 H₂0(0) -2 Br (aq) - Vo²+ (aq) + H₂O( -NO(g) + 2 H₂O(1) — CIO; (aq) -Ag(s) -Fe²+ (aq) -) HyOz(ag) MnO₂ (aq) 1.00 0.96 0.95 0.80 0.77 0.70 0.56 0.54 0.52 E° (V) 2.87 1.78 1.69 1.68 1.51 1.50 1.46 1.36 1.33 1.23 1.21 1.20 1.09
Consider the following half-reactions: Half-reaction E° (V) F2(g) + 2e → 2F*(aq) 2.870V Co2+*(aq) + 2e → Co(s) |-0.28OV 2+ Mg"(aq) + 2e → Mg(s) -2.37OV (1) The weakest oxidizing agent is: enter formula (2) The strongest reducing agent is: (3) The strongest oxidizing agent is: (4) The weakest reducing agent is: (5) Will Mg(s) reduce F2(g) to F"(aq)? (6) Which species can be reduced by Co(s)? If none, leave box blank.
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG° for the following redox reaction. Round your answer to 4 significant digits. L (s) + 6H,0 (1) +5Zn²™ (aq) → 21IO, (aq)+ 12H" (aq)+ 5Zn (s) |kJ x10
Consider the following standard reduction potentials: F2(g) + 2 e - 2 F (aq) E° = +2.87 V Mg2*(aq) + 2 e - Mg(s) E° = -2.37 V Under standard conditions, O Mg(s) is a stronger oxidizing agent than F (aq), and Mg2*(aq) is a stronger reducing agent than F2(g), O F (aq) is a stronger oxidizing agent than Mg(s), and F2(g) is a stronger reducing agent than Mg2*(aq). O F2(g) is a stronger oxidizing agent than Mg-"(aq), and Mg(s) is a stronger reducing agent than F (aq). O Mg2*(aq) is a stronger oxidizing agent than F2(g), and F(aq) is a stronger reducing agent than Mg(s).
5. A more complex example where other atoms are involved. Balance the following reaction in basic solution. r (aq) + MnO4 (aq) MnO, (s)+ BrO;" (aq) TABLE 19.1 Standard Electrode Potentials at 25 °C Reduction Half-Reaction E'(V) F + 20 H,0,(aq) + 2 H(aq)+2 e 2F(aq) 2.87 Stronger oxidizing agent Weaker 2 H,0 - PBSO (s) +2 H,0) -Mn0(s)+ 2 H,0) Mn (aq) 4 H,O) - Auts) 1.78 reducing agent PO,(s) + 4 H"(ag) + S0,2-(aq) + 2 e 1.69 Mno, (aq)+ 4 H'(aq) 3 e Mno, (aa) + 8 H (aq)+5 e Au (aq)+3e PbO,(s)+ 4 H(aa) + 2 e Cl,(g) + 2 e" 1.68 1.51 1.50 1.46 - P (ag) + 2 HO - 2a(aq) 1.36 1.33 Cr0, (aq) + 14 H'(ag) + 6 e 0+ 4 H (aq) + 4 e MnO(s)+4 H'(aq) +2 e 10, (aq) 6 H'(aq) + 5e Br+2e vo, (aq) + 2 H'(aq) + e NO, (aq) + 4 H°(aq) + 3e CIO+e 2 C"(aq) + 7 H,On - 2 H,O1) 1.23 Mn (aq) + 2 HyOV) 121 ulae) + 3 H,0() 2 Br (ag) - vo"(aq) +H,00 - NO + 2 H,O0 - CIO, (aa) - Agis) 1.20 1.09 1.00 0.96 0.95 Ag"(aa) + e 0.80 Fe (aq) + O+2 H'(aq)+2e - Fe*(aq) 0.77 - H,O,(ag) 0.70 Mn0, Taa) + e Mn0 (aa) 0.56 8) + 2 e…
Standard Reduction Potentials (Volts) at 25 °C F2 (g) + 2 e- 2 F- (aq) 2.870 O2(g) + 4 H3O+(aq) + 4 e- 6 H2O(l) 1.229 2 H2O(l) + 2 e- H2(g) + 2 OH-(aq) -0.828 Fe2+ (aq) + 2 e- Fe (s) -0.440 A 0.122 M neutral aqueous FeF2 solution is electrolyzed under 1 atm pressure using platinum electrodes.(a) Write the half-reactions expected to occur, taking into account the effect of the non-standard conditions on the electrode potentials.Half-reaction at anode: + + -> + + Half-reaction at cathode: + + -> + + (b) What is the expected decomposition potential? _______ V
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG for the following redox reaction. Round your answer to 2 significant digits. H₂(g) + 2OH(aq) + Zn²+ (aq) → 2H₂O (1) + Zn (s) kJ X S ? 1

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