Is my working method correct? I am also confused ablut the free body diagrams. Do i have to show the net force for that? ## Problem 2**Scenario:**A 2500 kg helicopter accelerates straight up at a constant 1.7 m/s². The helicopter can be modeled as a 2.6 m diameter sphere. - [C = 0.5, ρ = 1.2 kg/m³]**Tasks:**a. **Draw a free body diagram.**b. **Calculate the helicopter's height when its blades provide an upward force of 29 kN.**---### Solution- **Force Equation:** \[ \Sigma F_y = F_g - D \] \[ 29000 = mg - \frac{1}{2}C\rho A v^2 \]- **Drag Force Equation:** \[ D = \frac{1}{2} C \rho A v^2 \]- **Variables and Constants:** - m = 2500 kg (mass) - a = 1.7 m/s² (acceleration) - D = Drag Force - C = 0.5 (drag coefficient) - ρ = 1.2 kg/m³ (air density) - A = πr² = π(1.3)² (area of the sphere with radius 1.3 m) - v = final velocity- **Substituting the known values:** - Rearrange the force equation to find velocity \(v\): \[ 29000 - 2500 \times (9.8 + 1.7) = -\frac{1}{2}(0.5)(1.2)(\pi (1.3)^2)v^2 \] - Solving for \(v\), \[ v = 103.27 \, \text{m/s} \]- **Kinematic Equation:** \[ v^2 = u^2 + 2as \] \[ (103.27)^2 = 0 + 2 \times 1.7 \times s \] \[ s = 9879 \, \text{m} \] Therefore, the helicopter's height is approximately **9880 m**.

Name: Is my working method correct? I am also confused ablut the free body d
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: Is my working method correct? I am also confused ablut the free body diagrams. Do i have to show the net force for that? ## Problem 2**Scenario:**A 2500 kg helicopter accelerates straight up at a constant 1.7 m/s². The helicopter can be modeled as a