Euler's method is a numerical method for generating a table of values (xi, yi) that approximate the solution of the differential equation y' = f(x,y) with boundary condition y(xo) = yo. The first entry in the table is the starting point (xo, yo.). Given the entry (xi, yi ), then entry (xi+1, yi+1) is obtained using the formula xi+1 = xi + Dx and yi+1= yi + OxOf(xi, yi). Where h is the small value called step size. use c++ code and Use Euler's method to estimate the value of y when x= 2.5 for the solution of the differential equation y' = x+3y/x with the boundary condition y(1) = 1. Take Ox = 0.1, the exact solution of this differential equation is y = 2x^3-x^2. Compare your approximation values with the exact value.

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Euler's method is a numerical method for generating a table of values (xi, yi) that approximate
the solution of the differential equation y' = f(x,y) with boundary condition y(xo) = yo. The first
entry in the table is the starting point (xo, yo.). Given the entry (xi, yi), then entry (xi+1, yi+1) is
obtained using the formula xi+1= xi + Ox and yi+1 = yi + OXOF(xi , yi ). Where h is the small value
called step size.
use c++ code and Use Euler's method to estimate the value of y when x 2.5 for the solution of the differential
equation y' =x+3y/x with the boundary condition y(1) = 1. Take Ox = 0.1, the exact solution of
this differential equation is y = 2x^3- x^2.
.Compare your approximation values with the exact value.
Transcribed Image Text:Euler's method is a numerical method for generating a table of values (xi, yi) that approximate the solution of the differential equation y' = f(x,y) with boundary condition y(xo) = yo. The first entry in the table is the starting point (xo, yo.). Given the entry (xi, yi), then entry (xi+1, yi+1) is obtained using the formula xi+1= xi + Ox and yi+1 = yi + OXOF(xi , yi ). Where h is the small value called step size. use c++ code and Use Euler's method to estimate the value of y when x 2.5 for the solution of the differential equation y' =x+3y/x with the boundary condition y(1) = 1. Take Ox = 0.1, the exact solution of this differential equation is y = 2x^3- x^2. .Compare your approximation values with the exact value.
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