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Ethanoyl Chloride reacts with Ethanol to yield Ethyl Ethanoate and gaseous Hydrochloric Acid. Calculate the Change in Enthalpy of the esterification reaction. Given the following thermochemical data: /2H2(g) +¹/2Cl2(g) → HCl(g) 2C(s) + 3H2(g) + ¹/2O2(g) → CH3CH₂OH(1) 2C(s) + 1¹/2H2(g) + ¹/2O2(g) + ¹/2Cl2(g) → CH3COCI 4C(s) + 4H₂(g) + O2(g) → CH3COOCH₂CH3) AH-92.3 kJmol-¹ AH-278.0 kJmol-¹ AH = -275.0 kJmol-¹ AH-481.0 kJmol-¹

Ethanoyl Chloride reacts with Ethanol to yield Ethyl Ethanoate and gaseous Hydrochloric Acid. Calculate the Change in Enthalpy of the esterification reaction. Given the following thermochemical data: /2H2(g) +¹/2Cl2(g) → HCl(g) 2C(s) + 3H2(g) + ¹/2O2(g) → CH3CH₂OH(1) 2C(s) + 1¹/2H2(g) + ¹/2O2(g) + ¹/2Cl2(g) → CH3COCI 4C(s) + 4H₂(g) + O2(g) → CH3COOCH₂CH3) AH-92.3 kJmol-¹ AH-278.0 kJmol-¹ AH = -275.0 kJmol-¹ AH-481.0 kJmol-¹

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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Example 3 - Hess Law Ethanoyl Chloride reacts with Ethanol to yield Ethyl Ethanoate and gaseous Hydrochloric Acid. Calculate the Change in Enthalpy of the esterification reaction. Given the following thermochemical data: ¹/2H2(g) + ¹/₂Cl2(g) → HCl(g) 2C(s) + 3H2(g) + ¹/2O2(g) → CH3CH₂OH(1) 2C(s) + 1¹/2H2(g) + ¹/2O2(g) + ¹/₂Cl2(g) → CH3COCI(1) → CH3COOCH₂CH3(1) 4C(s) + 4H2(g) + O2(g) Answer: AHesterification=-20.3 kJ mol-¹ AH-92.3 kJmol-¹ AH-278.0 kJmol-¹ AH-275.0 kJmol-¹ AH-481.0 kJmol-¹
Transcribed Image Text:Example 3 - Hess Law Ethanoyl Chloride reacts with Ethanol to yield Ethyl Ethanoate and gaseous Hydrochloric Acid. Calculate the Change in Enthalpy of the esterification reaction. Given the following thermochemical data: ¹/2H2(g) + ¹/₂Cl2(g) → HCl(g) 2C(s) + 3H2(g) + ¹/2O2(g) → CH3CH₂OH(1) 2C(s) + 1¹/2H2(g) + ¹/2O2(g) + ¹/₂Cl2(g) → CH3COCI(1) → CH3COOCH₂CH3(1) 4C(s) + 4H2(g) + O2(g) Answer: AHesterification=-20.3 kJ mol-¹ AH-92.3 kJmol-¹ AH-278.0 kJmol-¹ AH-275.0 kJmol-¹ AH-481.0 kJmol-¹
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