Ethane is chlorinated in a continuous reactor: C2H6 +Cl2 → C2H5CI + HCI Some of the product monochloroethane is further chlorinated in an undesired side reaction: C2H5CI +Cl2→ C2H4CI2 + HCl a. Take a basis of 100.0 mol of C2H5CI produced. Assume that the feed contains only ethane and chlorine and that all of the chlorine is consumed. How many degrees of freedom remain (use atomic balances)? b. The reactor is designed to yield a 11.0% conversion of ethane and a selectivity of 10.0 mol C2H5CI / mol C2H4CI2 with a negligible amount of chlorine in the product gas. Calculate the feed ratio (mol Cl2/mol C2H6). i

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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**Ethane Chlorination Process**

Ethane is chlorinated in a continuous reactor through the following reaction:

\[ \text{C}_2\text{H}_6 + \text{Cl}_2 \rightarrow \text{C}_2\text{H}_5\text{Cl} + \text{HCl} \]

Some of the monochloroethane produced undergoes further chlorination in an undesired side reaction:

\[ \text{C}_2\text{H}_5\text{Cl} + \text{Cl}_2 \rightarrow \text{C}_2\text{H}_4\text{Cl}_2 + \text{HCl} \]

### Calculations and Considerations

**a. Degrees of Freedom in the Reactor System**

1. Base the calculation on 100.0 mol of \(\text{C}_2\text{H}_5\text{Cl}\) produced.
2. Assume the feed contains only ethane and chlorine, with complete consumption of chlorine.
3. Determine the degrees of freedom using atomic balances.

**b. Reactor Design Specifications**

1. The reactor achieves an 11.0% conversion of ethane.
2. Selectivity is 10.0 mol \(\text{C}_2\text{H}_5\text{Cl}\) per mol \(\text{C}_2\text{H}_4\text{Cl}_2\).
3. Chlorine presence in the product gas is negligible.

**Calculations Required**

1. Calculate the feed ratio (mol \(\text{Cl}_2\)/mol \(\text{C}_2\text{H}_6\)).
2. Calculate the fractional yield of monochloroethane.

These calculations help in understanding the reactor efficiency and the extent of side reactions, essential for optimizing industrial processes.
Transcribed Image Text:**Ethane Chlorination Process** Ethane is chlorinated in a continuous reactor through the following reaction: \[ \text{C}_2\text{H}_6 + \text{Cl}_2 \rightarrow \text{C}_2\text{H}_5\text{Cl} + \text{HCl} \] Some of the monochloroethane produced undergoes further chlorination in an undesired side reaction: \[ \text{C}_2\text{H}_5\text{Cl} + \text{Cl}_2 \rightarrow \text{C}_2\text{H}_4\text{Cl}_2 + \text{HCl} \] ### Calculations and Considerations **a. Degrees of Freedom in the Reactor System** 1. Base the calculation on 100.0 mol of \(\text{C}_2\text{H}_5\text{Cl}\) produced. 2. Assume the feed contains only ethane and chlorine, with complete consumption of chlorine. 3. Determine the degrees of freedom using atomic balances. **b. Reactor Design Specifications** 1. The reactor achieves an 11.0% conversion of ethane. 2. Selectivity is 10.0 mol \(\text{C}_2\text{H}_5\text{Cl}\) per mol \(\text{C}_2\text{H}_4\text{Cl}_2\). 3. Chlorine presence in the product gas is negligible. **Calculations Required** 1. Calculate the feed ratio (mol \(\text{Cl}_2\)/mol \(\text{C}_2\text{H}_6\)). 2. Calculate the fractional yield of monochloroethane. These calculations help in understanding the reactor efficiency and the extent of side reactions, essential for optimizing industrial processes.
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