) Ethane dissociates into methyl radicals at 700.OC with a rate constant of 5.50x10-4s-1.  If the activation energy is 384kJ/mol, what would be the rate constant at 870.OC?

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1) Ethane dissociates into methyl radicals at 700.OC with a rate constant of 5.50x10-4s-1.  If the activation energy is 384kJ/mol, what would be the rate constant at 870.OC?

**Reaction Analysis and Mechanism Proposal**

**Main Reaction:**

\[ 2 \text{NO} + \text{O}_2 \rightarrow 2 \text{NO}_2 \]

- **Observed Rate Changes:**
  - The reaction rate doubles if the \(\text{O}_2\) concentration doubles while \(\text{NO}\) concentration is unchanged.
  - The reaction rate quadruples if the \(\text{NO}\) concentration doubles while \(\text{O}_2\) concentration remains unchanged.

**Questions and Mechanism Proposals:**

**a. Rate Law Expression:**
- Determine the rate law expression for the above reaction and label your answer appropriately in the quiz.

**Proposed Mechanisms:**

**Proposal I:**
- **Step 1:** \(\text{NO} + \text{O}_2 \rightleftharpoons \text{NO}_3\) (fast equilibrium)
- **Step 2:** \(\text{NO} + \text{NO}_3 \rightarrow \text{NO}_2 + \text{NO}_2\) (slow, rate-determining step, RDS)

**Proposal II:**
- **Step 1:** \(\text{NO} + \text{NO} \rightleftharpoons \text{N}_2\text{O}_2\) (slow, RDS)
- **Step 2:** \(\text{O}_2 + \text{N}_2\text{O}_2 \rightarrow \text{N}_2\text{O}_4\) (fast)
- **Step 3:** \(\text{N}_2\text{O}_4 \rightarrow \text{NO}_2 + \text{NO}_2\) (fast)

**b. Predicted Rate Laws:**
- Write a predicted rate law for each proposed mechanism, ensuring no intermediates appear in the expression. Show your detailed work and label your answers on the scratch paper clearly.

**c. Mechanism Evaluation:**
- Determine which proposed mechanism (I or II) aligns with the rate law expression identified previously. Provide your reasoning to receive credit, and label your answer clearly on the scratch paper.
Transcribed Image Text:**Reaction Analysis and Mechanism Proposal** **Main Reaction:** \[ 2 \text{NO} + \text{O}_2 \rightarrow 2 \text{NO}_2 \] - **Observed Rate Changes:** - The reaction rate doubles if the \(\text{O}_2\) concentration doubles while \(\text{NO}\) concentration is unchanged. - The reaction rate quadruples if the \(\text{NO}\) concentration doubles while \(\text{O}_2\) concentration remains unchanged. **Questions and Mechanism Proposals:** **a. Rate Law Expression:** - Determine the rate law expression for the above reaction and label your answer appropriately in the quiz. **Proposed Mechanisms:** **Proposal I:** - **Step 1:** \(\text{NO} + \text{O}_2 \rightleftharpoons \text{NO}_3\) (fast equilibrium) - **Step 2:** \(\text{NO} + \text{NO}_3 \rightarrow \text{NO}_2 + \text{NO}_2\) (slow, rate-determining step, RDS) **Proposal II:** - **Step 1:** \(\text{NO} + \text{NO} \rightleftharpoons \text{N}_2\text{O}_2\) (slow, RDS) - **Step 2:** \(\text{O}_2 + \text{N}_2\text{O}_2 \rightarrow \text{N}_2\text{O}_4\) (fast) - **Step 3:** \(\text{N}_2\text{O}_4 \rightarrow \text{NO}_2 + \text{NO}_2\) (fast) **b. Predicted Rate Laws:** - Write a predicted rate law for each proposed mechanism, ensuring no intermediates appear in the expression. Show your detailed work and label your answers on the scratch paper clearly. **c. Mechanism Evaluation:** - Determine which proposed mechanism (I or II) aligns with the rate law expression identified previously. Provide your reasoning to receive credit, and label your answer clearly on the scratch paper.
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