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etermine AH/kJ for the following reaction using the listed enthalpies of action: N;Ha(1) + 2 H2O:(g)→N:(g) + 4 H:O(1) E(1) + 02 (g) → N2 (g) + 2 H20 (1) (g) + 1/2 02 (g) → H20 (1) (g) + 02 (g) H2O2 (1) Arº/kJ - -622.3 kJ AHº/kJ = -285.8 kJ AH°/kJ - -187.8 kJ pe your answer.

etermine AH/kJ for the following reaction using the listed enthalpies of action: N;Ha(1) + 2 H2O:(g)→N:(g) + 4 H:O(1) E(1) + 02 (g) → N2 (g) + 2 H20 (1) (g) + 1/2 02 (g) → H20 (1) (g) + 02 (g) H2O2 (1) Arº/kJ - -622.3 kJ AHº/kJ = -285.8 kJ AH°/kJ - -187.8 kJ pe your answer.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Final answer should be in KJ. Show all work on a separate piece of paper and submit work in part B. Clearly label question # and answer. Failure to show work will result in a zero for this question. Determine AH/kJ for the following reaction using the listed enthalpies of reaction: N2H4(1) + 2 H2O2(g) →N2(g) + 4 H2O(1) N2H4 (1) + 02 (g) → N2 (g) + 2 H20 (1) H2 (g) + 1/2 02 (g) → H20 (1) H2 (g) + 02(g) → H2O2 (1) Â#º/kJ AH°/kJ AH°/kJ = -187.8 kJ = -622.3 kJ = -285.8 kJ Type your answer.
Transcribed Image Text:Final answer should be in KJ. Show all work on a separate piece of paper and submit work in part B. Clearly label question # and answer. Failure to show work will result in a zero for this question. Determine AH/kJ for the following reaction using the listed enthalpies of reaction: N2H4(1) + 2 H2O2(g) →N2(g) + 4 H2O(1) N2H4 (1) + 02 (g) → N2 (g) + 2 H20 (1) H2 (g) + 1/2 02 (g) → H20 (1) H2 (g) + 02(g) → H2O2 (1) Â#º/kJ AH°/kJ AH°/kJ = -187.8 kJ = -622.3 kJ = -285.8 kJ Type your answer.
Expert Solution
Step 1

Use the concept of Hess law to get the Answer 

Multiply equation 2 by 2 and equation 3 by 2 and reverse it (equation 3) and add equation 1,2,3 to get ∆H rxn.

 

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